We have to use the functions:
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7
Solution :
Amounts spent on a trip : $31.11, $25.01, $18.53, $14.37, $24.16, $21.91
Confidence interval = 80%
Average amount spent = 8 to 9 years old
One sample T confidence interval
μ : Mean of variance
80% of confidence interval results :
Using statistical software,
Variable : data
Sample mean : 22.515
Std. Err. = 2.3479945
DF = 5
L. limit : 19.049632
U. Limit : 25.980368
SD = 5.75
Critical value = 1.476
Answer:
Step-by-step explanation:
xy = 300
x + y = 50 Solve for y
y = 50 - x substitute into xy = 300
x(50 - x) = 300 Remove the brackets.
50x - x^2 = 300 Bring the left to the right.
0 = x^2 - 50x + 300
This is a quadratic. It will have 2 solutions.
a=1
b = - 50
c = 300
Put these into the quadratic equation.
It turns out that x has two values -- both plus
x1 = 42.03
x2 = 6.97
x1 + y1 = 50
42.03 + y = 50
y = 50 - 42.03
y = 7,97
(42.03 , 7.97)
====================
x2 + y2 = 50
6.97 + y2 = 50
y2 = 50 - 6.97
y2 = 43.03
(6.97 , 43.03)
Answer:
D is correct
Step-by-step explanation:
A is incorrect because the lesser than is .001 higher
B is wrong since is .18 higher
C is wrong because its not equalone is .9 higher
