Find a common denominator between the two (this case it would be 18) and bring the fractions up, so 10/9 would be 20/18, and 3/2 would be 27/18. Then, multiply across, and simplify to lowest terms.
The area of a circle is the size of the 2-dimensional space inside the circle's
closed curved boundary.
The area can be calculated in terms of known linear measurements of the circle:
-- Area = (π) x (radius)²
-- Area = (π/4) x (diameter)²
-- Area = (1/2) x (circumference) x (radius)
-- Area = (1/4) x (circumference) x (diameter)
Any of these formulas will give you the area. The one you decide to use
just depends on what you already know about the circle.
Answer:
my best guess is answer choice c.
Answer:
Fencing needed = 20.8 units
Step-by-step explanation:
From the figure attached,
Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).
We have to find the length of fence required to cover the triangular garden.
Amount of fencing required = Perimeter of the triangular garden
Perimeter of the garden = AB + BC + AC
Formula to get the distance between A and B,
d = ![\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
AB =
= ![\sqrt{37}](https://tex.z-dn.net/?f=%5Csqrt%7B37%7D)
BC =
= ![\sqrt{37}](https://tex.z-dn.net/?f=%5Csqrt%7B37%7D)
AC =
=
Perimeter = ![\sqrt{37}+\sqrt{37}+\sqrt{74}](https://tex.z-dn.net/?f=%5Csqrt%7B37%7D%2B%5Csqrt%7B37%7D%2B%5Csqrt%7B74%7D)
= 6.08 + 6.08 + 8.60
= 20.76
≈ 20.8 units
Therefore, amount of fencing required to cover the triangular park is 20.8 units.