Complete question :
designs a board game in which a card is drawn on each turn. • A blue card means move forward 4 squares. • A red card means move back 6 squares. Liam suggests adding some other cards to Sia's game Part A Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card. How many spaces forward or backward does a player move after drawing a yellow card? Justify your answer.
Answer:
2 squares backward
Step-by-step explanation:
Given the rule :
Blue card = 4 squares forward
Red card = 6 squares backward
Yellow card = drawing a blue followed by a red
Spaces moved after drawing a yellow card:
Yellow equals :
Blue = + 4 squares ; then
Red = - 6 squares
Net total movement :
Blue + red
+4 + (-6)
4 - 6
- 2
2 squares backward
Answer:
<em>Trapezoid ABCD was reflected across the y-axis and then translated 7 units up.</em>
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Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Answer:
7 is the answer.
Step-by-step explanation:
In equations like this, you would solve the numbers in the parenthesis first, and then gradually do: Multiplication -> Division -> addition -> subtraction.
Therefore, -18 / 9 is -2.
-2 * 2 would be -4,
11 + (-4) would be 7.
Answer : 7.