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3 years ago

A pendulum takes 6.0 seconds to swing through 5 complete cycles. What is the period of the pendulum?

1 answer:

6 0

When you look at this, you might not be sure which way to divide ...
Should you divide 6 by 5 or 5 by 6 ?

Here's a case where you can use your units to decide.

The question wants to know the 'period'. That's a length of time,
so the answer needs to have units of time.

If you divide 'cycles' be 'time', you'll get 'cycles/second'.
That's Hz. It's frequency, not time.

If you divide 'time' by 'cycles', you'll get 'seconds/cycle'.
That's time, and it's exactly the definition of 'period'.

Period = (6 seconds) / (5 cycles)

= (6 / 5) seconds/cycle

= 1.2 seconds

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worty [1.4K]

Answer:

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Explanation:

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3 years ago

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On a Vernier Caliper, how do you know which mark to use on the very top scale?

madreJ [45]

Answer

To know where it starts we look where the zero mark of the vernier scale starts. The make just before reaching where the zero mark is marks the value to use.

Explanation

A vernier caliper is an instrument that is used to measure the diameter of small circular objects such as diameter of a wires, thickness of an iron sheet.

The objects to be measured is place between the jaws of the calipers.

The vernier scale has two scales, the vernier scale and the main scale which is the very top scale. To know where it starts we look where the zero mark of the vernier scale starts. The make just before reaching where the zero mark is marks the value to use.

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3 years ago

Consider a hydrogen atom in the n = 1 state. The atom is placed in a uniform B field of magnitude 2.5 T. Calculate the energy di

dlinn [17]

Answer:

$E=29\times 10^{-5}eV$

Explanation:

For n-=1 state hydrogen energy level is split into three componets in the presence of external magnetic field. The energies are,

$E^{+}=E+\mu B$ ,

$E^{-}=E-\mu B$ ,

$E^{0}=E$

Here, E is the energy in the absence of electric field.

And

$E^{+} and E^{-}$ are the highest and the lowest energies.

The difference of these energies

$\Delta E=2\mu B$

$\mu=9.3\times 10^{-24}J/T$ is known as Bohr's magneton.

B=2.5 T,

Therefore,

$\Delta E=2(9.3\times 10^{-24}J/T)\times 2.5 T\\\Delta E=46.5\times 10^{-24}J$

Now,

$Delta E=46.5\times 10^{-24}J(\frac{1eV}{1.6\times 10^{-9}J } )\\Delta E=29.05\times 10^{-5}eV\\Delta E\simeq29\times 10^{-5}eV$

Therefore, the energy difference between highest and lowest energy levels in presence of magnetic field is $E=29\times 10^{-5}eV$

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3 years ago

What controls whether a lava flow is aa or pahoehoe

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Explanation:

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3 years ago

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You are at rest with respect to the car.
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