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Andrej [43]
3 years ago
14

A pendulum takes 6.0 seconds to swing through 5 complete cycles. What is the period of the pendulum?

Physics
1 answer:
photoshop1234 [79]3 years ago
6 0
When you look at this, you might not be sure which way to divide ...
Should you divide  6 by 5  or  5 by 6 ?

Here's a case where you can use your units to decide.

The question wants to know the 'period'.  That's a length of time,
so the answer needs to have units of time.

If you divide 'cycles' be 'time', you'll get  'cycles/second'.
That's Hz.  It's frequency, not time.

If you divide 'time' by 'cycles', you'll get 'seconds/cycle'.
That's time, and it's exactly the definition of 'period'.

            Period  =  (6 seconds) / (5 cycles)

                         =    (6 / 5)  seconds/cycle

                         =     1.2  seconds 
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Answer:

1960Joules

Explanation:

Since we are not told what too find, we can as well find the Gravitational Potential Energy.

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3 years ago
An FM radio station broadcasts electromagnetic radiation at a frequency of 93.5 MHz. The wavelength of this radiation is _______
Alborosie

Answer:

3.21

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength


c is the speed of light having value 3\times 10^8\ m/s

Given, Frequency = 93.5 MHz = 93.5\times 10^{6}\ Hz

Thus, Wavelength is:

Wavelength=\frac{c}{Frequency}

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7 0
3 years ago
A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?
OlgaM077 [116]

Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

v_{f} =v_{o} + a*t

where:

Vf = final velocity = 1200 [km/h]

Vo = initial velocity = 25 [km/h]

t = time = 2 [min] = 2/60 = 0.0333 [h]

1200 = 25 + (a*0.0333)

a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]

3 0
3 years ago
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