Answer:
35.35 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 20 m/s
Angle of projection (θ) = 30°
Acceleration due to gravity (g) = 9.8 m/s²
Range (R) =.?
The range (i.e how far away) of the ball can be obtained as follow:
R = u² Sine 2θ /g
R = 20² Sine (2×30) / 9.8
R = 400 Sine 60 / 9.8
R = (400 × 0866) / 9.8
R = 346.4 / 9.8
R = 35.35 m
Therefore, the range (i.e how far away) of the ball is 35.35 m
Answer:
c. probablistic view of nature.
Explanation:
According to the problem of particle in a box in one dimension. If the particle energy E is taken less than the height of the barrier V.
Then with the help of classical mechanics it can be prove that the particle can not cross the barrier but according to the quantum mechanics, there is a small but a finite probability to cross the barrier.
Therefore by the above discussion it can be concluded that quantum mechanics can be thought as a probablistic view of nature.
Potential energy = mgh
Potential energy = 10 x 9.8 x 1.3
Potential energy = 127.4 J