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Aneli [31]
3 years ago
14

A car is behind a truck going 25 m/s on the highway. The car’s driver looks for an opportunity to pass, guessing that his car ca

n accelerate at 1.0 m/s^2. He gauges that he has to cover the 20 m length of truck, plus10 m clear room at the rear of the truck and 10 m more at the front of it. In the oncoming lane, he sees a car approaching, probably also travelling at 25 m/s. He estimates that the car is about 400 m away, should he attempt the pass? Give details
Physics
1 answer:
user100 [1]3 years ago
8 0

Answer:

No he should not attempt the pass

Explanation:

Let t be the time it takes for the car to pass the truck. The driver should ONLY attempt to pass when the distance covered by himself plus the distance covered by the oncoming car is less than or equal 400 m (a near miss)

At acceleration of 1m/s2 and a clear distance of 10 + 20 + 10 = 40 m, we can use the following equation of motion to estimate the time t in seconds

s = at^2/2

40 = 1t^2/2

t^2 = 80

t = \sqrt{80} = 8.94 s

Within this time frame, the first car would have traveled a total distance of the clear distance (40m) plus the distance run by the truck, which is

8.94 * 25 = 223.6m

So the total distance traveled by the first car is 223.6 + 40 = 263.6m

The distance traveled by the 2nd car within 8.94 s at rate of 25m/s is

8.94 * 25 = 223.6 m

So the total distance covered by both cars within this time frame

223.6 + 263.6 = 487.2m > 400 m

So no, he should not attempt the pass as we will not clear it in time.

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Colt1911 [192]

Answer:

Messenger RNA (mRNA), molecule in cells that carries codes from the DNA in the nucleus to the sites of protein synthesis in the cytoplasm (the ribosomes). The molecule that would eventually become known as mRNA was first described in 1956 by scientists Elliot Volkin and Lazarus Astrachan.

Explanation:

Hope It Helps ..

5 0
3 years ago
Help? 25 points and will give brainliest!
ladessa [460]

Answer: 44.89 times

Explanation:

Given that the earth's average velocity is about 6.7 times faster than that of planetoid Makemake

Given that the formula involved is:

R2/R1 = (V1/V2)^2

Let V1 = earth velocity and R1 = earth orbital distance

While R2 = Makemake velocity and R2 = orbital distance.

Since the earth's average velocity is about 6.7 times faster than that of planetoid Makemake, then,

V1/V2 = 6.7

Substitute this in the formula above

R2/R1 = (6.7)^2

R2/R1 = 44.89

Cross multiply

R2 = 44.89R1

Therefore, Makemake's orbit is about 44.89 times larger than the earth's orbit.

8 0
3 years ago
The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2551
RUDIKE [14]

Answer:

0.7 kg m²

Explanation:

F = force exerted applied by muscle in a professional boxer = 2551 N

r = length of lever arm = 3.15 cm = 0.0315 m

α = angular acceleration of the forearm = 115 rad/s²

I = moment of inertia of the boxer's forearm

τ = Torque applied by muscle in a professional boxer

Torque is given as

τ = I α = r F

Inserting the values

I (115) = (0.0315) (2551)

I = 0.7 kg m²

7 0
3 years ago
A stone tied at one end of the string is whirled in vertical circle, where is the tension in the string be maximum and minimum?
Ber [7]
<h3>answer</h3>

The minimum velocity required for a object to rotate in a verticle plane is v

1

=

5

gr.

So, at bottom point, T

max

=mv

1

2

/r+mg=6mg.

At top-most point velocity is v

2

=gr.

So, T

min

=mv

2

2

/r−mg=0

So T

max

−T

min

=6mg=2×g⇒m=1/3 kg

4 0
3 years ago
100 meters toward the shore in 25 seconds
Rzqust [24]

Answer:

The speed of a turtle is 4m/s

Explanation:

speed = distance/time

distance = 100m

time = 25s

s = 100/25

= 4m/s

6 0
3 years ago
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