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Katena32 [7]
3 years ago
12

A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure

reaches 0.510 atm. What is its final volume?
Chemistry
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

  • Initial volume of the gas (V₁): 656.0 mL
  • Initial pressure of the gas (P₁): 0.884 atm
  • Final volume of the gas (V₂): ?
  • Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

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Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
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Answer:

34.7mL

Explanation:

First we have to convert our grams of Zinc to moles of zinc so we can relate that number to our chemical equation.

So: 6.25g Zn x (1 mol / 65.39 g) = 0.0956 mol Zn

All that was done above was multiplying the grams of zinc by the reciprocal of zincs molar mass so our units would cancel and leave us with moles of zinc.

So now we need to go to HCl!

To do that we multiply by the molar coefficients in the chemical equation:

\frac{0.0956g Zn}{1 } (\frac{2 mol HCl}{1molZn})

This leaves us with 2(0.0956) = 0.1912 mol HCl

Now we use the relationship M= moles / volume , to calculate our volume

Rearranging we get that V = moles / M

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4 years ago
Proper significant figure: 27.01 + 14.369
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<h2>put the bigger number on top then add </h2>

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41.369

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