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Katena32 [7]
2 years ago
12

A gas occupying a volume of 656.0 mL at a pressure of 0.884 atm is allowed to expand at constant temperature until its pressure

reaches 0.510 atm. What is its final volume?
Chemistry
1 answer:
7nadin3 [17]2 years ago
5 0

Answer:

1.14 × 10³ mL

Explanation:

Step 1: Given data

  • Initial volume of the gas (V₁): 656.0 mL
  • Initial pressure of the gas (P₁): 0.884 atm
  • Final volume of the gas (V₂): ?
  • Final pressure of the gas (P₂): 0.510 atm

Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL

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Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
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Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

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