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krok68 [10]
3 years ago
14

1 Write the chemical symbols for following elements: Nitrogen-

Chemistry
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

Look below

Explanation:

Nitrogen: N

Phosphorus: P

Bromine: Br

Zinc: Zn

Potassium: K

Magnesium: Mg

Hope this helps(would be very grateful if you mark this answer branliest bc i need for lvl up)

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Help me answer this please
Vlad1618 [11]
Its a scam dont press the link
3 0
3 years ago
What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)
Andrei [34K]

Answer:

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

pH = pKa + log(salt÷acid)      ........................1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

pH = 3.65    

4 0
4 years ago
If the pOH of a cesium hydroxide solution is known to be 4.00. what is the (OH)? *Please round your answer to the appropriate nu
Snowcat [4.5K]

Answer:

i going to be aniston i would say take a gess

4 0
3 years ago
Compared to CH4,NH3 has:
vitfil [10]

a) NH₃ molecules have stronger intermolecular attractions than CH₄ molecules.

Explanation:

Ammonia molecules have stronger intermolecular attractions compared to methane.

Ammonia molecules have london dispersion forces and hydrogen bonds between their molecules.

Methane molecules have only london dispersion forces in their structure.

  • hydrogen bonds are very strong attractive forces between molecules in which the hydrogen of a molecule is attracted by a more electronegative atom of another usually oxygen, nitrogen and fluorine.
  • London dispersion forces are weak forces of attraction between heteronuclear atoms.

Learn more:

Hydrogen bonds brainly.com/question/10602513

#learnwithBrainly

3 0
3 years ago
After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905
julia-pushkina [17]

The sign's glass absorbed 25466.7 J

<h3>Further explanation</h3>

Given

The temperature of glass :  23.5 °C to 65.5 °C

mass = 905 g

the specific heat capacity = 0.67 J/g °C

Required

Heat absorbed

Solution

Heat absorbed by sign's glass can be formulated :

\tt Q=m.c.\Delta T

ΔT=65.5 - 23.5 = 42

\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}

5 0
3 years ago
Read 2 more answers
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