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aleksandr82 [10.1K]
3 years ago
9

Zeke knows that there are several layers of sediment underneath his town. The top layer is soil, the next layer is clay, and the

next layer is made up of gravel. He suspects that polluted water from a nearby mine is passing through one of these layers and making it into a local river. What could Zeke do to figure out how the polluted water might be moving from the mine to the river? A. He could build a model of the mine and test how deep it can go before it collapses. B. He could remove water from the mine and test it for certain pollutants. C. He could build a model of the soil layers and test if water passes through any of them. D. He could pour polluted water on the ground and test how long it takes for it to reach the river.
Chemistry
2 answers:
Eddi Din [679]3 years ago
8 0

Answer:

He could add a model of soil layers.

Explanation: C

defon3 years ago
3 0

Answer:

The answer is C

Explanation:

Got it right

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Name an element that has the same number of electron energy levels as Calcium (Ca)?
Lerok [7]

Answer:

aluminum?

Explanation:

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3 years ago
A carbon-12 atom has a mass of 12.00000 amu. The mass of a proton is 1.00728 amu, and the mass of a neutron is 1.00866 amu. 
Oksi-84 [34.3K]

Answer:

hell

Explanation:

8 0
3 years ago
The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa
Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of MgCl_2 (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of MgCl_2 (solute) = 3.37 g

First we have to calculate the mass of solute.

\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2

\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g

Now we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0
3 years ago
PLEASE HELP ASAP
erma4kov [3.2K]

In the so called rain shadow effect we have interaction between all of the four major Earth spheres. When we have a coastal region where there's a high mountain range, the part of the mountain that is facing the sea will differ a lot from the part of the mountain that is on the other side. The water from the sea evaporates. The water vapor makes the air wet. The warm and wet air masses from the sea will come to the coastline, once they reach the mountain they will start to accumulate as they can not pass through it. As they accumulate rainfall appears. The rainfall contributes to a lush vegetation on this side of the mountain (windward side). The rain shadow effect appears on the leeward side of the mountain, and it mostly gets dry, strong, downward winds. These conditions result in drier climate, much less vegetation, and much increased erosion. Thus we can easily see that we have in this case interaction between the hydrosphere (the sea and the rainfall), the geosphere (the ground, soil, rocks), biosphere (the vegetation), and atmosphere (the winds, the clouds).

6 0
4 years ago
Please answer, please answer please answer please answer<br>my last 2 chemistry question. ​
scoundrel [369]

Answer:

1. filtration and evaporation

2. i) water is added to the sand and salt mixture

ii) then the mixture is filtrated and so the sand and the salt water was seperated

iii) the salt water is heated with the help of burner until the water gets evaporated

iv) after the water gets evaporated, the salt is remained in the container

3. observation:

  • on adding water to the mixture, the salt is completely dissolved in the water
  • when filtrated the sand is seperated from the salt water
  • now the salt water when heated with the burner until the evaporation, the water is evaporated
  • the salt is precipitated and remained in the container

4. cautions:

  • while using the burner, we should be cautious with fire
  • the container that is heated should be holded with the help of a cloth to avoid heat
7 0
3 years ago
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