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s344n2d4d5 [400]
3 years ago
9

10) Calculate the energy change for the formation of LiCl(s) from its elements in their standard states and the following tabula

ted information: ?
1 Li(s) + 1/2 C12(s) — LiCl(s)
2 Li+(g) + Cl-(s) -- LiCl(s)
3 Li(s) — Li(g)
4 1/2 Cl2(g) - Cl(g)
5 Cl(g) + e- →Cl-(3) Li(g) → Lit(g) + e-
1-853 kJ/mol
2+159.4 kJ/mol
3+121.7 kJ/mol
4-348.6 kJ/mol
5+520.2 kJ/mol

A) +1305.7 kJ/mol
B) +296.9 kJ/mol
C) -400.3 kJ/mol
D) -627.2 kJ/mol ​
Chemistry
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

-400.3 kJ/mol

Explanation:

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a 10.99g sample of NaBr contains 22.34% Na by mass. Considering the law of constant composition (define proportions), how many g
leonid [27]

Given :

A 10.99 g sample of NaBr contains 22.34% Na by mass.

To Find :

How many grams of sodium does a 9.77g sample of sodium bromine contain.

Solution :

By law of constant composition , in any given chemical compound, the elements always combine in the same proportion with each other.

Therefore , percentage of Na by mass in NaBr will be same for every amount .

Percentage of Na in 9.77 g NaBr is 22.34 % too .

Gram of Na = 9.77\times \dfrac{22.34}{100}=2.18\ g .

Hence , this is the required solution .

7 0
3 years ago
How many molecules of ethane are present in 64.28 liters of ethane gas (C2H6) at STP
Rom4ik [11]

Answer : The molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

Solution :

At STP,

22.4 L volume of ethane present in 1 mole of ethane gas

64.28 L volume of ethane present in \frac{64.28L}{22.4L}\times 1mole=2.869moles of ethane gas

And, as we know that

1 mole of ethane molecule contains 6.022\times 10^{23} molecules of ethane

2.869 moles of ethane molecule contains 2.869\times 6.022\times 10^{23}=17.277\times 10^{23} molecules of ethane

Therefore, the molecule of ethane present in 64.28 L of ethane gas at STP is, 17.277\times 10^{23} molecule.

4 0
3 years ago
Read 2 more answers
Elements of modern periodic table are arrang in ---Group 2A elements are called ------ and group 7A element table are called....
pentagon [3]

Answer:

c) atomic number / alkaline earth metals/ and halogens

Explanation:

Elements of modern periodic table are arrang in atomic number; for its electron configuration and its chemical properties. This arrangement shows periodic trends.

Alkaline earth metals are a group of elements that are located in group 2 of the Periodic Table and are the following: Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), Barium (Ba) and Radio (Ra).

The Halogens are the chemical elements that form group 17 (XVII A, previously used) or group VII A of the periodic table: fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At) and teneso (Ts)

8 0
3 years ago
Each molecule of lycopene contains 40 atoms of carbon (plus other atoms). The mass percent of carbon in lycopene is 84.49%. What
IrinaK [193]

Answer: 568g/mol

Explanation:

It should be noted that there are 40 atoms of carbon in lycopene.

Since mass of 1 carbon = 12g/mol

Mass of 40 carbon atoms = 40 × 12g/mol = 480g/mol

Let the molar mass of lycopene be represented by x.

Therefore the molar mass of carbon = x × mass percent of carbon in lycopene

x × 84.49% = 480g/mol

x × 0.8449 = 480g/mol

x = 480/0.8449

x = 568g/mol

The molar mass of lycopene is 568g/mol

5 0
2 years ago
What volume of solution gives the desired moles?
motikmotik

Answer:

1. 0.073L

2. 0.028L

3. 0.014L

Explanation:

The volume for the different solutions are obtained as shown below:

1. Mole = 0.53mol

Molarity = 7.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.53/7.25

Volume = 0.073L

2. 0.035mol from a 1.25M

Mole = 0. 035mol

Molarity = 1.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.035/1.25

Volume = 0.028L

3. Mole = 0.0013mol

Molarity = 0.090M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.0013/0.090

Volume = 0.014L

8 0
3 years ago
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