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Bad White [126]
3 years ago
7

If you have 10g of Fe and 20 g of oxygen, how much product will you have?

Chemistry
1 answer:
ddd [48]3 years ago
3 0

Answer:

20 grams of methamphetamine

Explanation:

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Use the periodic table to identify the number of core electrons and the number of valence electrons in each case below.Magnesium
ser-zykov [4K]

Answer:

10 core 2 valence

Explanation:

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3 years ago
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Which tool is most suitable for a chemist to measure the mass of a liquid
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Chemists use beakers, flasks, burets and pipets to measure the volume of liquids. Plz mark as brainliest

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What are the coefficients of the balanced reaction? _CH4 + _CI2 ➡ _CCI4 + _HCI​
stealth61 [152]

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CH4 + 4Cl2 --> CCl4 + 4HCl

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7 0
3 years ago
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Stomach acid is predominately hydrochloric acid. Write the balanced chemical equation for the neutralization reaction between HC
bogdanovich [222]

Answer:

HCl + Mg(OH2)  ---> MgCl2 + H2O

Explanation:

hydrochloric acid + magnesium hydroxides  ==> magnesium Chloride (a salt) + Water

HCl + Mg(OH2)  ---> MgCl2 + H2O

8 0
3 years ago
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