Explanation:
A compound is defined as follows.
- Compounds are pure substance.
- The atoms bonded in a compound are in specific proportion.
- A compound is formed by chemical combination.
- For a compound, melting point and boiling point is defined.
A mixture is defined as follows.
- Mixtures are impure substance.
- The bonded atoms in a mixture are in any proportion.
- A mixture is formed by physical combination.
- For a mixture, melting point and boiling point is not defined.
On changing the amount of one substance will affect the formation of compound as a compound requires atoms to be bonded in a specific proportion. Whereas changing the amount of one substance will not affect the formation of mixtures as atoms can be bonded in any proportion in a mixture.
Answer:
C Is The Correct Answer Because The Deeper The Rock Is The Older It Is So The Top Is The Youngest And The Bottem Is The Oldest
A certain radioactive isotope has a half life of one hour. I you start with 1.0 g of the material at 1:00 P. M. 0.5 grams will be present at 2:00 P.M. on the same day.
<h3>What is half Life ?</h3>
Half life is the amount of time required to reduce to one half of its initial value. The symbol of half life is .
<h3 /><h3>How to calculate the quantity remaining when half life given ?</h3>
It is expressed as:
where,
N(t) = quantity remaining
N₀ = initial quantity
n = half life that have passed
Now put the values in above expression we get
=
= 0.5 gram
Thus from the above conclusion we can say that A certain radioactive isotope has a half life of one hour. I you start with 1.0 g of the material at 1:00 P. M. 0.5 grams will be present at 2:00 P.M. on the same day.
Learn more about the Half life here: brainly.com/question/25750315
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The Ksp of Mg(OH)2 in water is 1.8 x 10-<span>11. This means that in pure water, Mg(OH)2 has a solubility of:
</span>∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
<span>which is equal to
</span>1.65 x 10-4<span> mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL
If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
</span>1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL