Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean total cholesterol level of all males.
Number of sample, n = 355
Mean, u = 185 mg
Standard deviation, s = 16
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
185 +/- 1.96 × 16/√355
= 185 +/- 1.96 × 0.849
= 185 +/- 1.66404
The lower end of the confidence interval is 185 - 1.66404 =183.336
The upper end of the confidence interval is 185 + 1.66404 = 186.66
Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg
Answer:
D. 118°
Step-by-step explanation:
x = 118° { being corresponding angles }
Answer: 5 units
Step-by-step explanation:
Answer:
Null hypothesis is: U1 - U2 ≤ 0
Alternative hypothesis is U1 - U2 > 0
Step-by-step explanation:
The question involves a comparison of the two types of training given to the salespeople. The requirement is to set up the hypothesis that type A training leads to higher mean weakly sales compared to type B training.
Let U1 = mean sales by type A trainees
Let U2 = mean sales by type B trainees
Therefore, the null hypothesis (H0) is: U1 - U2 ≤ 0
This implies that type A training does not result in higher mean weekly sales than type B training.
The alternative hypothesis (H1) is: U1 - U2 > 0
This implies that type A training indeed results in higher mean weekly sales than type B training.
Answer:
RL=5x+28 and
RO=8X-11
diagonal of square bisect equally the side
:.5x+28=8x-11
11+28=8x-5x
39=3x
x=39/3=13
<u>RY</u><u>=</u><u>RL</u><u>=</u><u>5</u><u>x</u><u>+</u><u>2</u><u>8</u><u>=</u><u>5</u><u>×</u><u>1</u><u>3</u><u>+</u><u>2</u><u>8</u><u>=</u><u>9</u><u>3</u><u>If the answer is 93, move to </u><u>answer</u><u>.</u>
