24 students are splitting 7 pizzas. How much pizza will each student get?

PLEASEEEEEEEEEEEEEEEEEEEEEE Edgar rolls two six-sided number cubes. What is the probability that he rolls a 2 on

elena55 [62]

The probability that Edgar rolls a 2 on the first cube and a number less than 5 on the second cube is 1/9. Thus, the correct option is C.

<h3>What is Probability?</h3>

Probability helps us to know the chances of an event occurring.

$\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}$

There are a total of 36 outputs possible, while the number of desired outputs marked in the blue box is 4, therefore, the probability is,

Probability = 4/36 = 1/9

Hence, the probability that Edgar rolls a 2 on the first cube and a number less than 5 on the second cube is 1/9. Thus, the correct option is C.

Learn more about Probability:

brainly.com/question/795909

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8 0

2 years ago

*will give brainliest*

andriy [413]

I think the answer is one solution

3 0

2 years ago

A circle has a sector with are of (17/2)pi and a central angle of (17/90)pi radians. What is the area of the circle? Either ente

MAXImum [283]

This circle has a sector area of 17pi/2 and a central angle of 17pi/90.

So, the whole angle of the circle would be 2pi. To find the area of a sector, you can use the formula A=R*Angle

17pi/2= R* 17pi/90
R=45

A=45^2 * pi
A=90 pi or 282.6

7 0

3 years ago

Look at this table of values. What is the y-intercept?

ratelena [41]

Answer:

I think y=3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome

Scorpion4ik [409]

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

$X= X_1 + X_2 \\ \\ \\EX= EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0$

$Cov(x,y) = Var(X_1) +Var(X_2) \\ \\ =\dfrac{1}{2}(1+1) + \dfrac{1}{2}(1+1) \\ \\ = \dfrac{1}{2}(2)+ \dfrac{1}{2}(2) \\ \\ = 1+1 \\ \\ =2$

$Var (X) = Var (X_1+X_2)\\ \\ = 2 \ Var(X_1) \\ \\ = 2 \times (1) \\ \\ = 2$

$Var (Y) = Var (X_1 +X_2+X_3) \\ \\ = 3 \times Var(X_1) = \\ \\ = 3 \times 1\\ \\ = 3$

∴

$Corr(x,y) = \dfrac{2}{\sqrt{6}} \\ \\ = \dfrac{2}{\sqrt{2\times 3}} \\ \\= \sqrt{\dfrac{2}{3}}$

3 0

2 years ago