use the elimination method to solve the system of equations. choose the correct ordered pair x-y=2 2x+3y=14

Hurryyyy plzzz answer

Neporo4naja [7]

Answer:

the answer is 14 ounces of sugar

3 0

2 years ago

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An airplane is flying overhead at a constant elevation of 405 ft. A person is viewing the plane from a position 3040 ft from the

Gnoma [55]

Answer:

δL/δt = 634,38 ft/s

Step-by-step explanation:

A right triangle is shaped by ( y = distance between aircraft and ground which is constant and equal to 405 f ) a person who is at ground level 3040 f away from the tower distance x = 3040 f and the line between the aircraft and the person. Then we can use Pythagoras theorem and write

L ( distance between aircraft and person )

L² = x² + y² or L² = x² + (405)²

Taken partial derivatives with respect to t we get:

2*L*δL/δt = 2*x*δx/t + 0

Then L*δL/δt = x*δx/dt

At the moment of the aircraft passing over the tower

x = 3040 ft δx/δt = 640 ft/s and L = √ ( 3040)² + (405)²

So L = √9241600 + 164025 L = √9405625 L ≈3066,9 ft

Then:

δL/δt = 3040*640/ 3066,9 units [ ft * ft/s / ft ] ft/s

δL/δt = 634,38 ft/s

5 0

2 years ago

Evaluate the following using<br> powers of ten rules.<br> 9.4326<br> x 100

KengaRu [80]

Answer: 943.26

Step-by-step explanation:

9.4326

x 100

------------

943.26

5 0

2 years ago

how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?

VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

$\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32$

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

6 0

2 years ago

A jewelry store has 212.75 ounces of 14-carat gold in stock. (a) how many custom necklaces can be manufactured if each requires

Nonamiya [84]

Answer:

a. The number of custom necklaces that can be manufactured if each requires 2 7/8 ounces of gold is 74 necklaces.

b. The value of the gold in each necklace is $1761

Step-by-step explanation:

(a) Number of necklaces

2 $7/8$ ounces of gold=2.875

No of necklaces=212.75oz x 1 necklaces/2.875oz

=74 necklaces

(b)Value of gold in each necklace

There are 2.875 oz of 14K gold in each necklace. Pure gold is 24K.

Mass of pure gold=2.875oz x 14k/24k

=1.677083oz

Pure 24K gold is worth $1050/oz.

Value of pure gold=1.677oz x 1050/1oz

= 1760.9 dollars

The value of the gold in each necklace is $1761

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6 0

1 year ago

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