3 years ago

Question is predict the grade that someone would earn if they spent 14 hours per week watching TV? I need a number

Mathematics

1 answer:

nasty-shy [4]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Write this polynomial in standard form :8x^2 - 4x^3 + 12 - 5x

rodikova [14]

Hello from MrBillDoesMath

Answer: -4x^3 + 8x^2 -5x + 12

Discussion:

Standard for for a polynomial meas tne power of x descend so standard fro of

8x^2 - 4x^3 +12 -5x is

-4x^3 + 8x^2 -5x + 12

Note: the problem statements shows this ":8x^2". I didn't know how to deal with the ":" character so simply ignored it.

Thank you,

Mr. B

3 0

3 years ago

25 POINT GIVEAWAY MONKE GANG

kobusy [5.1K]

Answer:

thank you for the points.

7 0

3 years ago

Read 2 more answers

An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio

olga2289 [7]

Answer:

a) $E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

b) $E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

Step-by-step explanation:

We assume the following distribution given:

Y 0 1 2 3

P(Y) 0.60 0.25 0.10 0.05

Part a

We can find the expected value with this formula:

$E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

Part b

If we want to find the expected value of $100 Y^2$ we need to find the expected value of Y^2 and we have:

$E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)$

And replacing we got:

$E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

4 0

3 years ago

Write the number in two other forms. 40,023,032

grin007 [14]

40,000,000 + 20,000 + 3,000 + 30 + 2

and

forty million twenty-three thousand thirty-two

3 0

3 years ago

I don't understand this question

Alex777 [14]

Answer:

B- 17

Step-by-step explanation:

Add 8+9

= 17

17 units away.

7 0

4 years ago

Read 2 more answers