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timofeeve [1]
3 years ago
12

Help me get this right no links

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

What's the question? or show a picture

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Help not to sure what its asking I thought it was 2 but there ain't a 2 ​
Shtirlitz [24]

the answer is d. this is due to the fact a proton weighs 2000 times more then a electron

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2 years ago
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3 A roller coaster car travels up a hill until it reaches the top, slowly goes over, and speeds down the hill and through the nu
STALIN [3.7K]

Answer:

3rd law

Explanation:

8 0
3 years ago
What is the net ionic equation for a reaction between HCl and NaOH
kodGreya [7K]

Answer:

What is the net ionic equation for a reaction between HCl and NaOH?

Explanation:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl

Hope that helped.

5 0
2 years ago
Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and
Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

            \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

The given data is as follows.

     mass = 500 g,         C_{p} = 24.4 J/mol K

     T_{h} = 500 K,          T_{c} = 250 K               

   Mass number of copper = 63.54 g /mol

Number of moles = \frac{mass}{/text{\molar mass}}

                                 = \frac{500}{63.54}

                                 = 7.86 moles

Now, equating the entropy change for both the substances as follows.

     7.86 \times 24.4 \times [T_{f} - 250] = 7.86 \times 24.4 \times [500 -T_{f}]

       T_{f} - 250 = 500 - T_{f}

          2T_{f} = 750

So,       T_{f} = 375^{o}C

  • For the metal block A,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

              = 24.4 log [\frac{375}{500}]

              = -3.04 J/ K mol

  • For the block B,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

                  = 24.4 log [\frac{375}{250}]

                  = 4.296  J/Kmol

And, total entropy change will be as follows.

                       = 4.296 + (-3.04)

                      = 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol  and change in entropy of block B is 4.296  J/Kmol.

8 0
3 years ago
The _______ of an atom are negatively charged. a. protons b. negatrons c. neutrons d. electrons
PIT_PIT [208]
Protons = +1
negatrons = -1
neutrons = 0
<span>electrons = -1
</span>
<span>negatrons are like positrons and they are subatomic particles and are not present in atoms 
</span>
so electrons are negatively charged and are present in atoms 

hope that helps
7 0
3 years ago
Read 2 more answers
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