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Lelechka [254]
3 years ago
7

To lift a load of 100 N a distance of 1 m an effort of 25 N must be applied over an inclined plane of length 4 m. What must be d

one to lift the load 2 m, using the same effort? A.Use an inclined plane of length 8 m.
B.Use an inclined plane of length 2 m.

C.Use an inclined plane of length 10 m

D.Use an inclined plane of length 16 m.
Chemistry
2 answers:
Rama09 [41]3 years ago
5 0

Answer: The correct answer is A) Use an inclined plane of 8 m

Work :

Work is defined as force applied to an object to move it to some distance . It is calculated as product of force and displacement .

W = F* d

Where : W =work (N-m) F = force (N) d = displacement (m)

When a body is lifted , work can be expressed as :

W = m*g*h ( h = height )

Also force due to gravitation can be given as

F = m* g

where :

g = gravitational acceleration (9.8 \frac{m}{s^2}

Hence Work can be written as : W = F * h

Given :

Force on load due to gravitation = 100 N Height = 2 m

Force applied = 25 N displacement = ?

Work done to lift the load to 2 m = F * h

= 100 N * 2 m = 200 N-m

Plugging W = 200 N-m in work formula

W = F* d

200 N-m = 25 N * d

Dividing both side by 25 N

\frac{200N-m}{25 N} =  \frac{25 N * d}{25 N}

d = 8 m

Hence, to lift the load using 25 N , the inclined plane of 8 m can be used .

Gala2k [10]3 years ago
4 0
The answer is A, use an inclined plane of length 8.
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1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P
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5 0
3 years ago
Read 2 more answers
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Valentin [98]

Answer:

(a) Pair 1: H₂S and HS⁻

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(b) Pair 1: HSO₄⁻ and SO₄⁻

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(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.

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