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3 years ago

25) If an object’s density is greater than 1.00 g/mL, it will ______________ in water.

Chemistry

1 answer:

NeTakaya3 years ago

7 0

Answer:

1- Option A = Sink

2- Option B = Float

Explanation:

1- If an object’s density is greater than 1.00 g/mL, it will sink in water.

For example, the density of aluminum is 2.7g/cm³. That is why it will sink in water.

2- If an object’s density is less than 1.00 g/mL, it will float in water.

For example, the density of oak is 0.7 g/cm³. That is why oak will float in water.

3- Given data:

Mass, m = 50 g

Volume, v = 10 cm3 ( 1ml = 1cm3)

Formula of density :

Density = mass/ volume

d = m/v

d = 50g/10cm3

d = 5 g/cm3

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SCORPION-xisa [38]

Answer:

NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.

Explanation:

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3 years ago

Which alkaline earth metal has the highest ionization energy? Refer to the periodic table.

Liula [17]

I’m pretty sure the answer is Barium. I hope it helps.

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3 years ago

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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔

Vilka [71]

Answer : The correct option is, (C) 1.1

Solution : Given,

Initial moles of $N_2O_4$ = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration $N_2O_4$ .

$\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}$

$\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M$

The given equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initially c 0

At equilibrium $(c-c\alpha)$ $2c\alpha$

The expression of $K_c$ will be,

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

where,

$\alpha$ = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

$K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}$

$K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}$

$K_c=1.066\aprrox 1.1$

Therefore, the value of equilibrium constant for this reaction is, 1.1

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2 years ago

What is the mass in grams of 358 mL of ethylene glycol?

frez [133]

The density of ethylene glycol is: D = 1.11 g/mL
D = m / V
and V = 358 mL
m = D * V
m = 1.11 g/mL * 358 mL
m = 397.38 g
Answer:
Mass is 397.38 g.

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3 years ago

A scientist is researching the solar system. How can the scientist best add to existing empirical evidence about the solar syste

Bogdan [553]

Answer:

The correct option is;

c. The scientist can make and record observations

Explanation:

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With the aid of empirical evidence, it is possible for researchers to find answers to question regarding topics that can vastly impact every day life.

With empirical evidence, it is possible to determine the effects of treatment in a study such as the invention of working car safety devices such as seat belts and airbags.

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3 years ago