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liq [111]
3 years ago
15

Hydrochloric acid is used to produce fertilizers and dyes, to pickle and clean metal products, and as a reagent in the photograp

hic and rubber industries. Which of the following is a chemical property of hydrochloric acid?
Liquid hydrochloric acid can vaporize into a gas at 48 degrees Celsius

All of these are chemical properties of hydrochloric acid

Hydrochloric acid is soluble in water

Hydrochloric acid reacts with the materials to produce bubbling, or fizzing, a gas, and heat.
Chemistry
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

Hydrochloric acid reacts with the materials to produce bubbling, or fizzing, a gas, and heat.

Explanation:

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Explanation:

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When we react a weak acid with a strong base of equal amounts and concentration, the component of the reaction that will have th
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Answer:

d. the conjugate base of the weak acid

Explanation:

The strong base (BOH) is completely dissociated in water:

BOH → B⁺ + OH⁻

The resulting conjugate acid (OH⁻) is a weak acid, so it remains in solution as OH⁻ ions.

By other hand, the weak acid (HA) is only slightly dissociated in water:

HA ⇄ H⁺ + A⁻

The resulting conjugate base (A⁻) is a weak base. Thus, it reacts with H⁺ ions from water to form HA, increasing the concentration of OH⁻ ions in the solution.

Therefore, the resulting solution will have a pH > 7 (basic).

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3 years ago
A chemist dissolves 797. mg of pure barium hydroxide in enough water to make up 60. mL of solution. Calculate the pH of the solu
topjm [15]

Answer:

13.20

Explanation:

Step 1: Calculate the moles of Ba(OH)₂

The molar mass of Ba(OH)₂ is 171.34 g/mol.

0.797 g × 1 mol/171.34 g = 4.65 × 10⁻³ mol

Step 2: Calculate the molar concentration of Ba(OH)₂

Molarity is equal to the moles of solute divided by the liters of solution.

[Ba(OH)₂] = 4.65 × 10⁻³ mol/60 × 10⁻³ L = 0.078 M

Step 3: Calculate [OH⁻]

Ba(OH)₂ is a strong base according to the following equation.

Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻

The concentration of OH⁻ is 2/1 × 0.078 M = 0.16 M

Step 4: Calculate the pOH

pOH = -log OH⁻ = -log 0.16 = 0.80

Step 5: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - 0.80 = 13.20

7 0
3 years ago
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