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3 years ago

8

4. The probability that a student is in a category can be approximated by the relative frequency. To the nearest hundredth, what

is the probability that a randomly selected student is a girl who wants to go skating?

1 answer:

LuckyWell [14K]3 years ago

6 0

4.6666666666667 or 4.7 is it multiple choice?

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(66 x 10) - (9.9 x 104)

Sidana [21]

66x10=660

9.9x104=1029.6

660-1029.6=-369.6

3 0

4 years ago

Read 2 more answers

Share $600 between Anna and Raman in the ratio 3:7 and 1:4

Ulleksa [173]

Answer:

3 : 7 =>

Anna = $180

Raman = $420

1 : 4 =>

Anna = $120

Raman = $480

Step-by-step explanation:

<u>Shares when ratio is 3 : 7</u>

Anna : Raman = 3 : 7

Sum of ratio 10

Anna's share=

$\frac{3}{10} \times 600 = \$ 180$

Raman 's share=

$\frac{7}{10} \times 600 = \$ 420$

<u>Shares when ratio is 1 : 4</u>

Anna : Raman = 1 : 4

Sum of ratio = 5

Anna 's share =

$\frac{1}{5} \times 600 = \$ 120$

Raman's share =

$\frac{4}{5} \times 600 = \$ 480$

8 0

3 years ago

Please solve this problem. I can't solve it! And can someone explain how to do it please??

s2008m [1.1K]

Answer:

1.23

Step-by-step explanation:

They already give u the amount of oz in a gram, so you would want to multiply 0.035 by 37.

6 0

3 years ago

At a team meeting, 80% of the tennis team was there. If there were 12

Illusion [34]

Answer:

15 people

Step-by-step explanation:

let x=total # of people on the team

80%=12

80/100=12/x

cross multiply

80x=1200

division property of equality (divide both sides by 80)

x=15

There are 15 people on the team.

8 0

3 years ago

Point B has coordinates (1,2). The x-coordinate of point A is -8. The distance between point A and point B is 15 units. What

Xelga [282]

Answer:

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

$l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}}$ (1)

Where:

$l_{AB}$ - Length of the line segment AB.

$x_{A}, x_{B}$ - x-coordinates of points A and B.

$y_{A}, y_{B}$ - y-coordinates of points A and B.

If we know that $l_{AB} = 15$ , $x_{A} = -8$ , $x_{B} = 1$ and $y_{B} = 2$ , then the possible coordinates of point A is:

$\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15$

$81 + (2-y_{A})^{2} = 225$

$(2-y_{A})^{2} = 144$

$2-y_{A} = \pm 12$

There are two possible solutions:

1) $2-y_{A} = -12$

$y_{A} = 14$

2) $2 - y_{A} = 12$

$y_{A} = -10$

The possible coordinates of point A are $A_{1} (x,y) = (-8, 14)$ and $A_{2} (x,y) = (-8, -10)$ , respectively.

8 0

3 years ago