Hey there,
I hope this answer solves your doubt.
<u>S</u><u>t</u><u>e</u><u>p</u><u>-</u><u>b</u><u>y</u><u>-</u><u>s</u><u>t</u><u>e</u><u>p</u><u> </u><u>Expla</u><u>n</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u><u>-</u>
The question is asking if the bonds between Carbon and Chlorine in CCl4 will be single, double or triple bonds.
<em>(</em><em>The structure of CCl4 </em><em>i</em><em>s attached as picture. Check it</em><em>)</em>
As per image, the structure consists of <u>Singl</u><u>e</u><u> </u><u>b</u><u>o</u><u>n</u><u>d</u><u>s</u><u>.</u> It is <u>4 single bonds</u>.
Answer:
solid at room temperature (with the exception of mercury)
usually shiny.
high melting point.
good conductor of heat.
good conductor of electricity.
low ionization energies.
low electronegativities.
malleable – able to be pounded into sheets.
Explanation:
Answer:
Explanation:
Kindly note that I have attached the complete question as an attachment.
Here, we are told that elimination occurs by an E2 mechanism. What this means is that the hydrogen and the halogen must be above and below for the reaction to proceed.
The possible products are as follows;
Please check attachment for complete equations and diagrams of compounds too.
1 μL = 10^-6 L by definition
So...
82 μL = 82x10^-6 L = 8.2x10^-5 L
Density is equal to the mass divided by the voulme.
So: 2.5 multiplied by 2.5 by 2.5.
Then: 295 divided by 16.625=18.88g/cm to the power 3