Question

A 2.714 gram sample of a hydrate of sodium carbonate is placed in a test

Answer 1

Answer:

$m_{water}=1.708g$

Explanation:

Hello!

In this case, since the total mass of the sample is 2.714 g and the mass of the anhydrous salt is 1.006 g; we infer the mass of water is:

$m_{water}=2.714g-1.006g\\\\m_{water}=1.708g$

Moreover, the percentage of water in the hydrate is calculated by dividing the mass of water by the mass of the total hydrate:

$\% water=\frac{1.708g}{2.714g}*100\% \\\\\% water=62.9\%$

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