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stepladder [879]
3 years ago
13

A 2.714 gram sample of a hydrate of sodium carbonate is placed in a test

Chemistry
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

m_{water}=1.708g

Explanation:

Hello!

In this case, since the total mass of the sample is 2.714 g and the mass of the anhydrous salt is 1.006 g; we infer the mass of water is:

m_{water}=2.714g-1.006g\\\\m_{water}=1.708g

Moreover, the percentage of water in the hydrate is calculated by dividing the mass of water by the mass of the total hydrate:

\% water=\frac{1.708g}{2.714g}*100\% \\\\\% water=62.9\%

Best regards!

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