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MatroZZZ [7]
4 years ago
12

What is 31 grams converted to milligrams

Chemistry
2 answers:
yKpoI14uk [10]4 years ago
6 0
31,000 milligrams is equal to 31 grams
Umnica [9.8K]4 years ago
3 0
31000 Milligrams Thank hope this was helpful.
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What do the elements in each pair have in common? k, kr be, mg ni, tc b, ge al, pb?
tensa zangetsu [6.8K]
The pairs are:
K, Kr - Same period
Be, Mg - Same group
Ni, Tc - Both are transition metals
B, Ge - Both are metaloids
Al, Pb - Both form inert oxides
4 0
3 years ago
Lithium
zimovet [89]

Answer:

The unknown metal could be calcium or magnesium.

Explanation:

Displacement of a metal from its chemical reaction is shown by the reaction known as single displacement reaction. The reactivity of metal is determined by the reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the reactivity series.

Metal B is more reactive than metal A.

The metal which easily displaced aluminium will lie above in the series but that same element cannot displace sodium, so it will lie below in the series.

Hence, from the series, we conclude that the unknown metal could be calcium or magnesium.

5 0
2 years ago
The compound before the arrow are called blank and the compound after the arrow are called blank
Norma-Jean [14]
First one is reactants and then second one is products
8 0
4 years ago
An opening volumetric cylinder filled with water at volume 0.003m after period of
raketka [301]

Answer:

= - 303.975 Joules

Explanation:

Given that:

The volume of the cylinder = 0.003 m^3

Now, to liters:

The volume = 0.003 *1000 L

= 3 L

For an open cylinder, we mean the atmospheric pressure is at standard condition.

Thus, the workdone = -PΔV

= - 1 atm (3 L)

= - 3 L atm

1 L atm to Joules

= 101.325 Joules

Therefore;

=- 3* 101.325 Joules

= - 303.975 Joules

7 0
4 years ago
What is the ph of a solution with a hydroxyl ion (oh-) concentration of 10-10 m? what is the ph of a solution with a hydroxyl io
krek1111 [17]
According to this formula:
pH = - log [H]
And, pOH = - log [OH] >>> (1)
Where, pH + pOH = 14  >>> (2)
∵ the hydroxide ion concentration = (OH-) = 10 ^ -10 M
from (1) and (2) and by substitution: 
∴ pOH = - log [10^-10] = 10 
∴ pH = 14 - 10 = 4 
3 0
3 years ago
Read 2 more answers
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