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alekssr [168]
3 years ago
11

Plastics are used in millions of objects we use every day. Why are plastics NOT considered natural resources?

Physics
2 answers:
jeka57 [31]3 years ago
4 0

Answer:

B

Explanation:

Yes plastic is artficial

Sati [7]3 years ago
4 0

Answer:

letter C. they are bad for the environment

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Answer:

I think its distance

Explanation:

when measuring how far a p.o art u can use mm

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3 years ago
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Sound and light are both found as _____, with a variety of ____. The sun, a source of light waves specifically, releases a type
Novosadov [1.4K]

Answer:

Waves; wavelength; electromagnetic energy; ultraviolet light.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases.

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

Hence, sound and light are both found as waves, with a variety of wavelength. The sun, a source of light waves specifically, releases a type of electromagnetic energy. It can be found as UVA or UVB types. These lights give off different levels of ultraviolet light, some of wich can be harmful.

Additionally, the ultraviolet spectrum is divided into three categories and these are; UVA, UVB and UVC.

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2 years ago
Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science.
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7 0
3 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

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3 years ago
The period T of a simple pendulum depends
Alenkinab [10]

Answer:

too old

Explanation:

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