Answer:
the light will reflect parallel to the principal axis
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
Answer:
okay
Explanation:
(wish i could help but im just answering for points)
Answer:
A) 185.6 J
B) 9.396 x 10^14 J
C) 4x10^7 m/s
D) 20 m
E) 9.09x10^-8 sec
F) 9.09x10^-8 sec
Explanation:
Detailed explanation and calculation is shown in the image below
Answer:
the ball will go up 3s and down 3s
v=gt
where t=3s and g=9.8m/s^2
distance=v0(t)+(1/2)gt^2
where initial velocity (v0)=0
Explanation:
