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sattari [20]
3 years ago
15

Hello could yall answer my question ​

Physics
1 answer:
Rus_ich [418]3 years ago
8 0
Density is a physical property derived from mass devided by volume (first part of the question)




m=v*p (p is rho)
m=9.5*60 =570 g
Density of water is 1g/cm^3 (centimeter cubed)
You might be interested in
A. What quantum number of the hydrogen atom comes closest to giving a 61-nm-diameter electron orbit?
Black_prince [1.1K]

Answer:

a

  n  = 23

b

  v  = 87377.95 \ m/s

Explanation:

From the question we are told that

   The diameter is d = 61\ nm =  61 *10^{-9} \ m

   

Generally the radius electron orbit  is mathematically represented as

      r = \frac{61 *10^{-9}}{2}

=>   r = 3.05*10^{-8} \  m

This radius can also be represented mathematically  as

      r =  n^2 *  a_o

Here n is the quantum number and a_o is  the Bohr radius with a value

    a_o =  0.0529 *10^{-9} \ m

So

   n  =  \sqrt{\frac{3.05*10^{-8}}{ 0.059*10^{-9}} }

=>   n  = 23

Generally the angular momentum of the electron is mathematically represented as

          L  =  m * v *  r  =  \frac{n  *  h }{2 \pi}

Here  h is the Planck constant and the value is  h  =  6.626*10^{-34} J \cdot s

          m is the mass of the electron with values m  =  9.1*10^{-31} \  kg

         So

               v  =  \frac{23   *  6.626*10^{-34} }{2\pi * 9.1 *10^{-31}  * 3.05*10^{-8} }

                v  = 87377.95 \ m/s

       

3 0
3 years ago
A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to
irinina [24]

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

<h3>Frictional force between the block and the horizontal surface</h3>

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Learn more about frictional force here: brainly.com/question/4618599

8 0
2 years ago
4. How does the type of medium affect a sound wave?
jek_recluse [69]

Answer:

The type of medium affects a sound wave as sound travels with the help of the vibration in particles.

Explanation:

As different mediums have different amount and size of particles, for example, the speed of sound is faster through solid than liquid as solids have closely packed particles whereas liquids are loosely packed.

5 0
3 years ago
n deep space, sphere A of mass 47 kg is located at the origin of an x axis and sphere B of mass 110 kg is located on the axis at
Volgvan

Answer:

a)-1.014x 10^{-7J

b)3.296 x  10^{-7J

Explanation:

For Sphere A:

mass 'Ma'= 47kg

xa= 0

For sphere B:

mass 'Mb'= 110kg

xb=3.4m

a)the gravitational potential energy is given by

U_{i = -GMaMb/ d

U_{i= - 6.67 x 10^{-11} x 47 x 110/ 3.4 => -1.014x 10^{-7J

b) at d= 0.8m (3.4-2.6) and U_{i=-1.014x 10^{-7J

The sum of potential and kinetic energies must be conserved as the energy is conserved.

K_{i + U_{i= K_{f + U_{f

As sphere starts from rest and sphere A is fixed at its place, therefore K_{i is zero

U_{i= K_{f + U_{f

The final potential energy is

U_{f= - GMaMb/d

Solving for 'K_{f '

K_{f = U_{i + GMaMb/d => -1.014x 10^{-7 + 6.67 x 10^{-11} x 47 x 110/ 0.8

K_{f = 3.296 x  10^{-7J

6 0
3 years ago
Water is boiled in a pan on a stove at sea level. During 10 min of boiling, it is observed that 200 g of water has evaporated. T
diamong [38]

Answer:

Rate of heat is 45.1 kJ/min

Explanation:

Heat required to evaporate the water is given by

Q = mL

here we know that

L = 2.25 \times 10^6 J/kg

now we have

Q = (0.200)(2.25 \times 10^6 J/kg)

Q = 452.1 kJ

now the power is defined as rate of energy

P = \frac{Q}{t}

P = \frac{452.1 kJ}{10}

P = 45.1 kJ/min

6 0
3 years ago
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