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sattari [20]
3 years ago
15

Hello could yall answer my question ​

Physics
1 answer:
Rus_ich [418]3 years ago
8 0
Density is a physical property derived from mass devided by volume (first part of the question)




m=v*p (p is rho)
m=9.5*60 =570 g
Density of water is 1g/cm^3 (centimeter cubed)
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A student was taking a rock-climbing class that used an indoor climbing wall. Before he started, the instructor asked for his we
Wittaler [7]
F = m*g 
F = 88.6 * 10 = 886 N 
3 0
4 years ago
A planet orbits a star along an elliptical path from point X to point Y, as shown in the figure. In which of the following syste
8090 [49]

Answer:

The correct answer is Option D, the closed system containing the planet and the star.

Explanation:

To start, we need to define mechanical energy: the energy an object has from its motion and position.

The fundamental principle in physics is that the total energy in a closed system stays constant, even if it transforms. By saying "closed system," we refer to a system isolated from its surroundings. Energy never leaves the system; it only moves from one part to another.

This statement only applies to closed systems, however. An open system that interacts with its environment works differently. Energy may enter and leave the system through interaction with external forces, and this includes mechanical energy. For this reason, Option A and Option B are incorrect.

The remaining two options, C and D, only vary with the objects in the closed system. Option D includes the star; Option C does not.

However, we should take a closer look at Option C. Can an object have potential energy with itself? No, it cannot. It only has potential energy with other bodies. If the system is defined as the planet only, the only type of energy present is kinetic energy. We know a planet orbiting a star has more kinetic energy near and more gravitational potential energy further from its star. Thus it has less kinetic energy further from its star and less mechanical energy. Because of this, Option C is incorrect.

The only answer left is Option D. If we define the planet and star as a closed system, we find no net external force acting on it. Consequently, it obeys the law of conservation of energy. From prior reasoning, we know mechanical energy includes potential energy and kinetic energy and that the amounts of these energies vary with its orbit. As a result, mechanical energy is always conserved and always the same. In the end, the correct answer is Option D.

4 0
3 years ago
Until a train is a safe distance from the station, it must travel at 5 m/s. Once the train is on open track, it can speed up to
SIZIF [17.4K]

Answer:

5 m/s^2

Explanation:

The acceleration of the train is given by:

a=\frac{v-u}{t}

where:

u = 5 m/s is the initial velocity of the train

v = 45 m/s is the final velocity of the train

t = 8 s is the time taken for the train to increase the velocity

Substituting numbers into the formula, we find

a=\frac{45 m/s-5 m/s}{8 s}=5 m/s^2

5 0
4 years ago
Read 2 more answers
At a certain point in space, there is a potential of 800 V relative to zero. What is the potential energy of the system when a +
sammy [17]

To solve this problem we will apply the concepts related to electric potential and electric potential energy. By definition we know that the electric potential is determined under the function:

V = \frac{k_e q}{r}

k_e = Coulomb's constant

q = Charge

r = Radius

At the same time

U = \frac{k_e q_1q_2}{r}

The values of variables are the same, then if we replace in a single equation we have this expression,

U  = Vq

If we replace the values, we have finally that the charge is,

V = 800V

q = 1\mu C

U = (800V)(1*10^{-6}C)

U = 8*10^{-4}J

Therefore the potential energy of the system is 8*10^{-4} J

7 0
3 years ago
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
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