Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
Acceleration = (change in speed) / (time for the change)
Acceleration = (4 m/s) / (8 seconds)
Acceleration = 0.5 m/s²
Force = (mass) x (acceleration)
Force = (85 kg) x (0.5 m/s²)
Force = 42.5 Newtons
Answer:
∴ fractional compression = 1.34 × 10⁻²
Explanation:
given,
depth of Indian ocean = 3000 m
Bulk modulus of the water = 2.2 x 10⁹ N/m²
We know,
P = P₀ + ρgh
P₀ is the atmospheric pressure
P₀ = 10⁵ N/m²
ρ is the density of the water, 1000 Kg/m³
P = 10⁵ + 1000 × 9.8 × 3000 = 2.94 × 10⁷ N/m²
using formula,
B = P/{-∆V/V}
B is bulk modulus and { -∆V/V} is the fractional compression
∴ fractional compression = 1.34 × 10⁻²
Answer:
<h3>The answer is option A</h3>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>3.10 L</h3>
Hope this helps you
