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3 years ago

Write the equation in standard form for the circle x^2 + y^2 + 16x + 28 = 0.

Mathematics

1 answer:

GenaCL600 [577]3 years ago

6 0

Answer:

( x + 8 ) ^2+ y^2= 36

Step-by-step explanation:

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One base of a trapezoid is five times as long as the other. The height is the average of the two bases. The area is 441 square u

Gelneren [198K]

Answer:

The length of the longer base he 35 units

Step-by-step explanation:

Here, we want to find the length of the longer base of the trapezoid

Mathematically, we can find the area using the formula;

1/2( a + b) h

where a is the shorter base

b is the longer base

h is the height

Let the shorter base be x

The other base is 5 times this length and that makes 5 * x = 5x

Height is the average of both bases;

(x + 5x)/2 = 6x/2 = 3x

Substituting these in the formula, we have ;

1/2(x + 5x)3x = 441

3x(6x) = 882

18x^2 = 882

x^2 = 882/18

x^2 = 49

x^2 = 7^2

x = 7

But the longer base is 5x and that will be 5 * 7 = 35 units

4 0

2 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Mai is filling her fish tank. Water flows into the tank at a constant rate.

Shalnov [3]

Ok so the consent rate is 5 and 8

5 0

3 years ago

Read 2 more answers

Please do not skip it’s 9th grade math Please help me! thank you in advance:)

Gemiola [76]

Answer:

I cant read It very Well, but I'm Pretty Shure that it is C

Step-by-step explanation:

7 0

2 years ago

F F(x) = 8x, which of the following is the inverse of F(x)?

Alchen [17]

F(x) = 8x
y = 8x
x = 8y
x/8 = y
y = x/8
f^-1(x) = x/8

6 0

2 years ago