Answer:









Explanation:
Pipet is used to dispense a very small amount of liquid.
Test tube rack is used to hold multiple test tubes at the same time.
Test Table is used to view chemical reactions or hold or heat small amounts of substance.
Scoopula is used to dispense chemicals from a larger container.
Graduated cylinder is used to measure volume very precisely.
Bunsen burner is used to heat objects.
Beaker is used to transport heat or store substance.
Spot plate is used to observe the color changes of small quantities of a reacting mixture.
Goggles are used to protect the eyes from flying objects or chemical splashes.
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Answer:
1. The dye that absorbs at 530 nm.
Explanation:
The dye will absorb light to promote the transition of an electron from the HOMO to the LUMO orbital.
The higher the gap, the higher the energy of transition. The energy can be calculated by E = hc/λ, in which h and c are constants and λ is the wavelength.
The equation shows that the higher the energy, the higher the gap and the lower the wavelength.
Therefore, the dye with absorption at 530 nm has the higher HOMO-LUMO gap.
Answer:
Option a → 4 mol NH₃
Explanation:
This the unbalanced reaction
NH₃ + O₂ ⟶ N₂ + H₂O
The balanced reaction:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
4 mol of ammonia
3 mol of oxygen
2 mol of nitrogen
6 mol of water
In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=

%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%