Answer:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Explanation:
The reactions are:
(1) ClO⁻(aq) + H₂O(l) → HClO(aq) + OH⁻(aq) [fast]
(2) I⁻(aq) + HClO(aq) → HIO(aq) + Cl⁻(aq) [slow]
(3) OH⁻(aq) + HIO(aq) → H₂O(l) + IO⁻(aq) [fast]
By adding up the 3 equations we get:
ClO⁻(aq) + <em>H₂O(l)</em> + I⁻(aq) + <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> → <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> + Cl⁻(aq) + <em>H₂O(l)</em> + IO⁻(aq)
And by canceling common terms on both sides, we can get the overall equation:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Therefore, the overall equation is ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq).
I hope it helps you!
The amount of heat required that is used to change 1l of water into vapour at atmospheric pressure is known as latent heat of vaporisation
Answer:
Decomposition.
Explanation:
Decomposition Reactions T hose reactions in which a single substance (reactant) splits up into two or more simpler substances (products) are known as decomposition reactions. These reactions are carried out by supplying energy in form of heat, electricity or light which breaks that substance into simpler substances
Answer:
Explanation:
glucose-1-phosphate → glucose-6-phosphate, ΔGo = -7.28 kJ/mol
fructose-6-phosphate → glucose-6-phosphate, ΔGo = -1.67 kJ/mol
subtracting the equation
glucose-1-phosphate - fructose-6-phosphate = 0 , ΔGo = -7.28 - ( -1.67 ) kJ / mol
glucose-1-phosphate = fructose-6-phosphate ΔGo = - 5.61 kJ / mol
- ΔGo = RT lnK
5.61 x 10³ = 8.31 x 298 x lnK
lnK = 2.265
K = 9.63 .
Answer:
The answer to your question is b. CaCrO₄
Explanation:
Data
H₂CrO₄ reacts with Ca(OH)₂
Process
H₂CrO₄ is an acid and Ca(OH)₂ is a base then this is a neutralization reaction.
H₂CrO₄ is an acid and Ca(OH)₂ is a base.
In a neutralization reaction, the products will always be water and a binary or ternary salt.
In the reaction, the salt will be Calcium chromate
Balanced chemical reaction
H₂CrO₄ + Ca(OH)₂ ⇒ CaCrO₄ + 2H₂O