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2 years ago

A wave transfers from one place to another

2 answers:

4 0

A is a disturbance that transfers energy from one place to another. Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance.

Margarita [4]2 years ago

3 0

Answer:

mhm

Explanation:

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A 1.5 L sample of gas was collected at a pressure of 1.8 atm. What volume will the gas have if the pressure is reduced to 1.0 at

luda_lava [24]

P1V1=P2V2
(1.8)(1.5)=(1.0)V2
2.7=1.0 V2
2.7/1.0= 1.0/1.0V2
2.7=V2

6 0

2 years ago

Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb calorimeter has a

dexar [7]

Answer:

Its final temperature is 25.8 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)

When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.

In this case, you know:

Q= 14 kJ= 14,000 J

c= 3.55 $\frac{J}{g*C}$

m=1.20 kg= 1200 g (1 kg=1000 g)
Tfinal= ?
Tinitial= 22.5 °C

Replacing:

$14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)$

Solving:

$\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C$

3.3=Tfinal - 22.5 C

3.3 + 22.5=Tfinal

Tfinal= 25.8 °C

Its final temperature is 25.8 °C

3 0

2 years ago

Read 2 more answers

A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 60.00 gram sample of the alcohol p

marin [14]

Answer:

$C_2H_6O$

Explanation:

The first step is the calculation of the moles of $H_2O$ and $CO_2$ , so:

$114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2$

$70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O$

Now, in 1 mol of CO2 we have 1 mol of C and in 1 mol of $H_2O$ we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to calculate the grams of C and O and then do the substraction form the initial amount, so:

$2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C$