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Inga [223]
3 years ago
13

What is acid rain?

Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

THE RAIN OR PRECIPITATION WHICH IS ACIDIC IN NATURE IS CALLED ACID RAIN. WET AND DRY DEPOSITIONS ARE THE TWO TYPES OF ACID RAINS.UNIVERSAL INDICATOR IS USED TO DETERMINE COLOUR CHANGE AND HOW ACIDIC AND BASIC IS THE SOLUTION.

Explanation:

The rain which is acidic in nature is called acid rain. It is a precipitated form that contains acidic components such as sulphuric acid or nitric acid. The acid rain is of two types i.)wet deposition ii.)dry deposition

Wet deposition means the acid rain will be of wet form. Dry deposition means the acid rain contains dust,gasses, rain, snow, fog and hail.

Sulphuric dioxide and nitric oxides mix with water, oxygen and other chemicals in the air and becomes sulphuric acid and nitric acids that mix with precipitation and fall on to the ground.the precipitation is said to be acidic when its ph is below 5.2.

The different polyatomic ions that form acids are H+ and SO4-2 and H+ cation and NO3- anions.

A universal indicator is a mixture of indicators which show a colour change in a solution, which interprets how acidic or basic a solution is. A universal indicator can be in paper form or present in a form of a solution.The colours from yellow to red indicate an acidic solution, colours blue to violet indicate bases and green colour indicates that a solution is neutral.

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Pls help me no links
Assoli18 [71]

Answer:

mixture

Explanation:

6 0
3 years ago
Read 2 more answers
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
why do we heat the test tube in a glass beaker during a chemistry experiment and not directly over a flame?
bearhunter [10]
It is not directly over a flame because it depends on the substance you might not want to heat it too much.you never know what could happen
7 0
3 years ago
Ways to manage non-biodegradable waste​
Lisa [10]

Answer:

The following are some ways of safely disposing of non-biodegradable waste.

1. Take them to a local recycling facility. Separate metal, plastic, glass, and other non-biodegradable waste and store them ready for recycling.

2. Combustion and energy recovery.

3. Disposal at sanitary facilities.

4. Reduce.

5. Landfills.

Explanation: Hope it helps! ^_^"

(G00gle)

7 0
3 years ago
Không tính toán cụ thể mà lý luận để :
kotykmax [81]

Answer:

c) Tìm những chất có hàm lượng đồng bằng nhau trong 4 chất : CuO, Cu2O, CuS, Cu2S.

Explanation:

3 0
2 years ago
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