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Inga [223]
3 years ago
13

What is acid rain?

Chemistry
1 answer:
zloy xaker [14]3 years ago
8 0

THE RAIN OR PRECIPITATION WHICH IS ACIDIC IN NATURE IS CALLED ACID RAIN. WET AND DRY DEPOSITIONS ARE THE TWO TYPES OF ACID RAINS.UNIVERSAL INDICATOR IS USED TO DETERMINE COLOUR CHANGE AND HOW ACIDIC AND BASIC IS THE SOLUTION.

Explanation:

The rain which is acidic in nature is called acid rain. It is a precipitated form that contains acidic components such as sulphuric acid or nitric acid. The acid rain is of two types i.)wet deposition ii.)dry deposition

Wet deposition means the acid rain will be of wet form. Dry deposition means the acid rain contains dust,gasses, rain, snow, fog and hail.

Sulphuric dioxide and nitric oxides mix with water, oxygen and other chemicals in the air and becomes sulphuric acid and nitric acids that mix with precipitation and fall on to the ground.the precipitation is said to be acidic when its ph is below 5.2.

The different polyatomic ions that form acids are H+ and SO4-2 and H+ cation and NO3- anions.

A universal indicator is a mixture of indicators which show a colour change in a solution, which interprets how acidic or basic a solution is. A universal indicator can be in paper form or present in a form of a solution.The colours from yellow to red indicate an acidic solution, colours blue to violet indicate bases and green colour indicates that a solution is neutral.

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The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3
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Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Where,

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol  

k_2=2.3\times 10^8

T_2=280\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (280 + 273.15) K = 553.15 K  

T_2=553.15\ K  

k_1=4.8\times 10^8  

T_1=376\ ^0C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (376 + 273.15) K = 649.15 K  

T_1=649.15\ K  

So,  

\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)

E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol

E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol

E_a=22.87\ kJ/mol

<u>The activation energy for this reaction = 23 kJ/mol.</u>

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