B. When the subject matter is objective and informative
Options:
A. Operational
B. Tactical
C. Static
D. Strategic
D. Growth
Answer:D. Growth
Explanation:Growth plans are Activities put in place to enhance that an organisation attains its growth Objectives.
A Growth plan identifies potential opportunities for growth and makes the required resources available in irder to sponsor the potential opportunities.
A growth plan contains business elements which can help the a business Organisation identify the value of customers and how to meet the needs of the customers which will help to enhance the growth of the business through increased revenue.
Answer:
$200,000
Explanation:
As we know that
The net income is the income that is generated when we deduct all expenses incurred from all revenues generated that is reflected on the income statement
In mathematically,
Net income = Revenues earned - expenses incurred
= $450,000 - $250,000
= $200,000
The answer is<u> "demographic component".</u>
Population change results from the cooperation of demographic components: birth, demise and relocation. Along these lines, demography manages the point by point investigation of the three segments. With the estimation of such segments, different parts of the populace are broke down and deciphered. It designs and execute different advancement exercises. Birth, demise and movement are called demographic components, and additionally the deciding components of populace change since they influence the circumstance of the populace. In this way, the measure of the populace depends for the most part upon birth, passing and relocation.
Answer:
to maximize profit, farmer must use 0.208 pounds of fertilizers
Explanation:
For profit maximization, marginal revenue must be equal to marginal cost.
Here marginal product of fertilizer= 1-N/200
selling price per busher= $4
total marginal revenue= (1-N/200)× 4
Total cost of fertilizer= 1.2N
To maximize profit
Marginal cost= marginal revenue
1.2N= (1-N/200)× 4
4.8N= 1-N/200
N= 0.208 pounds
to maximize profit, farmer must use than 0.208 pounds of fertilizers
