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olga_2 [115]
3 years ago
8

When we use the SPDC model, we always include the following EXCEPT:

Mathematics
1 answer:
Sidana [21]3 years ago
4 0
B.!!!!!! !!!!
that’s the answer
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Pls pls help, thank you <3
Reika [66]

Answer:

  (x -1)² +(y -4)² = 25

Step-by-step explanation:

The equation of a circle in standard form is ...

  (x -h)² +(y -k)² = r² . . . . . . . circle with center (h, k) and radius r

The graph shows your circle has its center at (1, 4) and its radius is 5. Then the equation is ...

  (x -1)² +(y -4)² = 25

3 0
3 years ago
Make groups of ten. Write the tens and ones. 1) 90 Ones
Alisiya [41]
90  ones would make 9 tens. It makes 9 tens because theres a 0 after 90. The 0 represents another place value. You can write this as 9 groups of ten
7 0
3 years ago
Simplify the following expression by combining like terms.Select the most simplified expression 2w + 5w - 6 + 4w
KATRIN_1 [288]
Answer is 11w-6
Add all the like terms. So all with the w’s which is how I got 11 and then 6 stays the same hence the -6
4 0
2 years ago
Read 2 more answers
I HAVE A CYLINDER AND cone WITH THE
Vlad1618 [11]

Answer:

99 in³

Step-by-step explanation:

Let the radius and height of each be r and h in. respectively.

Write an equation for the volume of cone.

Volume of cone= ⅓πr²h

⅓πr²h= 33

Multiply both sides by 3:

πr²h= 99

Volume of cylinder= πr²h

We have found the value of πr²h previously, which is 99.

Thus, the volume of the cylinder is 99 in³.

6 0
2 years ago
100 POINTS AND BRAINLIEST
zysi [14]

Answer:

8 square units and \frac{40}{3} square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor \frac{1}{3}, then

\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.

2. Triangles ABC and DBE are similar with scale factor \frac{2}{3}, then

\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.

3. Thus, the area of the quadrilateral DFGE is

A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.

and the area of the quadrilateral ADEC is

A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.

4 0
3 years ago
Read 2 more answers
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