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2 years ago

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To earn a prize, sally had to sell at least 20 candy bars for the band fundraiser. What percentage of the candy bars did she nee

d to sell?

1 answer:

Verdich [7]2 years ago

8 0

Answer:

out of how many candy bars?

Step-by-step explanation:

You might be interested in

8 to 11 do it with equations thx

Alenkasestr [34]

Answer:

Step-by-step explanation:

8. $4\geq x+\frac{3}{4}$

$4(4\geq x+\frac{3}{4} )$

$16\geq 4x + 3$

$-3$ $-3$

$13\geq 4x$

$\frac{13}{4}\geq \frac{4x}{4}$

$\frac{13}{4} \geq x = x\leq \frac{13}{4}$

$x\leq \frac{13}{4}=3.25$

9. $x-3\leq -8$

$+3$ $+3$

$x\leq -5}$

10. $4\leq x-7$

$+7$ $+7$

$11\leq x=x\geq 11$

11. 6.9 < x - 2.3

+ 2.3 + 2.3

9.2 < x = x > 9.2

Hope this helps!

5 0

2 years ago

0.6(4-2x)=20.5-(3x+10)

solong [7]

The solution of 0.6(4-2x)=20.5-(3x+10) is x = 4.5

<u>Solution:</u>

Given, expression is 0.6 ( 4 – 2x ) = 20.5 – ( 3x + 10 )

We have to solve the above given equation for x.

Now, take the equation

$\rightarrow 0.6(4-2 x)=20.5-(3 x+10)$

We have to use BODMAS rule. BODMAS means sequence of operations which is brackets, order, division, multiplication, addition and then subtraction

On solving the brackets, we get

$\rightarrow 0.6 \times 4-0.6 \times 2 x=20.5-3 x-10$

Now multiplication is given preference

$\rightarrow 2.4-1.2 x=10.5-3 x$

$\rightarrow 3 x-1.2 x=10.5-2.4$

Now subtraction is done

$\rightarrow 1.8 \mathrm{x}=8.1$

Now division is performed

$\rightarrow x=\frac{8.1}{1.8}=4.5$

Hence, the value of x is 4.5

5 0

3 years ago

3÷2.58=<br> what's the answer i'm fr wut is the answer

Alex

Answer:

1.1627907

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A line has slope and yintercept 5. which answer is the equation of the line

ioda

Answer: if the y-intercept is 5, it's c. -3/4x + 5. Since it's ax+b a = slope b = y intercept

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

<u>Final answer</u>:-

$(y-6)^2 = 4 (x-1)$

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

5 0

3 years ago