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gayaneshka [121]
3 years ago
10

Consider the following equation. y = 1/3x + 10. Which of the following lines is perpendicular to the one a above ?

Mathematics
1 answer:
seraphim [82]3 years ago
5 0

Answer:

D. Y=3x+10

Step-by-step explanation:

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If a 50 foot cable supporting a circus tent
natta225 [31]

Step-by-step explanation:

using formula that cos= b/h

3 0
2 years ago
the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.
marshall27 [118]

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

3 0
3 years ago
Xiao's teacher asked him to rewrite the sum 60+90 the product of the GCF of the two numbers and a sum. Axial wrote 3(20+30). Wha
LuckyWell [14K]
60 + 90

GCF = 30

(30 * 2) + (30 * 3) = 30(2 + 3) <== the correct way

The mistake Axial made was he did not pick the greatest common factor...he picked 3 instead of 30.
4 0
2 years ago
Read 2 more answers
for the State Fair next month 132 people volunteer to plan the fairs activities the volunteers form 12 equal groups how many vol
MA_775_DIABLO [31]

Answer:

11

132/12

Step-by-step explanation:

7 0
2 years ago
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A florist is creating 10 centerpieces. Roses cost $2.50 each, lilies cost $4 each, and irises cost $2 each. A customer plans on
lana [24]

Answer:

8 Roses; 1 lilie ; 3 irises

Step-by-step explanation:

Let the number of roses be 'a' , number lilies be 'b' and number of irises be 'c'

$300 for 10 centerpieces means $30 per centerpiece. therefore,

2.5a+4b+2c = 30 .......................(1)

also each centerpiece must contain 12 flowers, therefore,

a+b+c=12 .................................(2)

also twice as much roses as the number of irises and lilies combined

a = 2(b+c)

a-2b-2c=0 ............................... (3)

a) System of equation are equations (1) , (2) & (3).

Writing a matrix equation

\left[\begin{array}{ccc}2.5a&4b&2c\\a&b&c\\a&-2b&-2c\end{array}\right]  = \left[\begin{array}{ccc}30\\12\\0\end{array}\right]

b) Solving the simultaneous equation,

from (3), a=2b+2c

substituting for 'a' in equation (1) and (2),

⇒ 2.5(2b+2c)+4b+2c=30

⇒ 5b + 5c + 4b + 2c = 30

⇒ 9b + 7c = 30 ..................... (4)

⇒ 2b + 2c + b + c = 12

⇒ 3b + 3c = 12

⇒ b = 4 - c ..............................(5)

Substituting (5) in (4)

9 (4 - c) + 7c = 30

36 - 9c+7c =30

36-30 = 2c

c = 3

b = 4-3 = 1

a = 2(3+1) = 8

3 0
3 years ago
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