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2 years ago

Is a quadrilateral a square?

Mathematics

2 answers:

telo118 [61]2 years ago

5 0

Answer:

If I were to be honest no Edit: yes it is

Step-by-step explanation:

No because a square has straight parrallel corners. But a quadrilateral has slanted parallel corners.

Hope that helped. But maybe wait for sumone else to answer too. : )

Edit: nvm my bad I was wrong

Alenkinab [10]2 years ago

3 0

Answer:

No but a square is a quadrilateral

Step-by-step explanation:

hope this helps :)

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What is -5x + 15 = 35 - 10x

dezoksy [38]

Answer:

x = 4

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

-5*x+15-(35-10*x)=0

Pull out like factors :

5x - 20 = 5 • (x - 4)

_________________________________________

Solve : 5 = 0

This equation has no solution.

A a non-zero constant never equals zero.

_________________________________________

Solve : x-4 = 0

Add 4 to both sides of the equation :

x = 4

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3 years ago

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3 years ago

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Evaluate the expression using the values in the left column to complete the table

egoroff_w [7]

Answer/Step-by-step explanation:

A. $4b + 3b$

Using b = 2

$4(2) + 3(2) = 8 + 6 = 14$

Using b = 4

$4(4) + 3(4) = 16 + 12 = 28$

Using b = 6

$4(6) + 3(6) = 24 + 18 = 42$

Using b = 8

$4(8) + 3(8) = 32 + 24 = 56$

Using b = 10

$4(10) + 3(10) = 40 + 30 = 70$

Using b = 2

$4(12) + 3(12) = 48 + 36 = 84$

B. $3(x - 2)$

Using x = 3

$3(3 - 2) = 3(1) = 3$

Using x = 5

$3(5 - 2) = 3(3) = 9$

Using x = 7

$3(7 - 2) = 3(5) = 15$

Using x = 9

$3(9 - 2) = 3(7) = 21$

Using x = 11

$3(11 - 2) = 3(9) = 27$

Using x = 13

$3(13 - 2) = 3(11) = 33$

C. $5(4a - 1)$

Using a = 2

$5(4(2) - 1) = 5(8 - 1) = 5(7) = 35$

Using a = 3

$5(4(3) - 1) = 5(12 - 1) = 5(11) = 55$

Using a = 4

$5(4(4) - 1) = 5(16 - 1) = 5(15) = 75$

Using a = 5

$5(4(5) - 1) = 5(20 - 1) = 5(19) = 95$

Using a = 6

$5(4(6) - 1) = 5(24 - 1) = 5(23) = 115$

Using a = 7

$5(4(7) - 1) = 5(28 - 1) = 5(27) = 135$

D. $6y - 2y + 4$

Using y = 2

$6(2) - 2(2) + 4 = 12 - 4 + 4 = 12$

Using y = 3

$6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16$

Using y = 5

$6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24$

Using y = 10

$6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44$

Using y = 8

$6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36$

Using y = 6

$6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28$

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2 years ago

FInd the value of x/

grandymaker [24]

Answer:

x=18

Step-by-step explanation:

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2 years ago

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

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3 years ago