Answer:
The correct answer is True.
Explanation:
In the kidney, the handle of Henle is a fork-like tube located in the nephrons. It is the portion of the nephron that leads from the proximal contoured tubule to the distal contoured tubule. The primary filtrate from the glomerulus passes into the proximal contoured tubule, which connects to the descending branch of the loop of Henle, which has low permeability to ions and urea (solutes) but is very permeable to water.
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I'm just doing the ones that you don't have numbers already for.
2.) just leave it alone and it's correct
3.) Mg + 2AgNo3 --> Mg(No3)2 + 2Ag
5.) just leave it alone and it's correct
8.) 10C3H8O3 + 15O2 --> 30CO2 + 4H2O
10.) P4 + 6Br2 --> 4PBr3
12.) 2FeCl3 + 6NaOH --> 2Fe(OH)3 + 6NaCl
13.) 2CH3OH + 3O2 --> 2CO2 + 4H2O
14.) 2Al + 3Cu(NO3)2 --> 2Al(NO3)3 + 3Cu
15.) 3CaCl2 + 2K3AsO4 --> Ca3(AsO4)2 + 6KCl
16.) 2NH3 --> N2 + 3H2
17.) 2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O
19.) Mg3N2 + 6H2O --> 3Mg(OH)2 + 2NH3
I hope this helps you!!
Answer:
It's the third option
Explanation:
Because the particles of the solid are very closed together and packed they can barely move, causing the item to have a fixed shape and volume.
Answer:
Plasma
Explanation:
Plasma is a substance which is extremely hot. The heat present in plasma, a gas, is provided as energy in order to split electrons and protons apart. Therefore, ions and electrons are formed as products. Plasma is a synonym to an 'ionized gas'.
Normally, the standard states, gases, liquids and solids, wouldn't produce such an outcome, as not enough energy is present to perform the splitting pattern. This can only occur for gases at extremely high temperatures.
Add 7 water atom to the right hand side to adjust the quantity of oxygen. Increase Cr(+3) by two to adjust the quantity of Cr. Duplicate Cl-by two to adjust the quantity of chlorine molecules.
Cr2O7[2-](aq) +2 Cl[-](aq) < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
Presently adjust that charges.
you have - 4 charges on the left hand side, while +18 charges on the right hand side, there for include 14H+ the left hand side to adjust the charges
Cr2O7[2-](aq) +2 Cl[-](aq)+14H+ < - >2 Cr[3+] (aq) + Cl2(g)+7H2O
take note of that the oxidation number of hydrogen in water is +1