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Natalka [10]
3 years ago
13

Which will contain the greater number of moles of potassium ion: 30.0 ml of 0.15 m k2cro4 or 25.0 ml of 0.080 m k3po4?

Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0
<span>30.0 ml of 0.15 m K2CrO4 solution will have more potassium ions. Let's see the relative number of potassium ions for each solution. Since all the measurements are the same, the real difference is the K2CrO4 will only have 2 potassium ions per molecule while the K3PO4 solution will have 3 potassium ions per molecule. K2CrO4 solution 30.0 * 0.15 * 2 = 9 K3PO4 solution 25.0 * 0.080 * 3 = 6 Since 9 is greater than 6, the K2CrO4 solution will have more potassium ions.</span>
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We will use boiling point formula:

ΔT = i Kb m 

when ΔT is the temperature change from the pure solvent's boiling point to the boiling point of the solution = 77.85 °C - 76.5 °C = 1.35

and Kb is the boiling point constant =5.03

and m = molality 

i = vant's Hoff factor

so by substitution, we can get the molality:

1.35 = 1 * 5.03 * m

∴ m = 0.27

when molality = moles / mass  Kg

           0.27 = moles /  0.015Kg

∴ moles = 0.00405 moles

∴ The molar mass = mass / moles
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5 0
3 years ago
6.0L of a gas exert a pressure of 2.5 atm. When the pressure is increased to 10.0atm what is the new volume of the gas
jeka57 [31]

Answer:

<h2>1.5 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

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From the question we have

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We have the final answer as

<h3>1.5 L</h3>

Hope this helps you

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2 years ago
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Answer:

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