For the titration we use the equation,
M₁V₁ = M₂V₂
where M is molarity and V is volume. Substituting the known values,
(0.15 M)(43.2 mL) = (2)(M₂)(20.5 mL)
We multiply the right term by 2 because of the number of H+ in H2SO4. Calculating for M₂ will give us 0.158 M. Thus, the answer is approximately 0.16M.
The formula that can be applied in this problem is W = Fd
where W is work, F is the force and d is distance. You have 450N and 3m, all
you have to do is to multiply it.
W = Fd
W = (450N) (3m)
W = 1350J
The answer is letter C.
It depends if it occurs naturally it has oxidation number of 0
but when it react with other element it has an oxidation number of -1
Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2
