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Deffense [45]
2 years ago
8

Give reason why think before you use a simple cell ?​

Physics
1 answer:
xxMikexx [17]2 years ago
8 0
I agree with the other dude
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B. A car is moving 4.0 m/s to the right. The car begins to accelerate at a rate of 1.5 m/s/s, to the right. After
Maurinko [17]
There you go, hope that helps.

7 0
2 years ago
A cube of side 6.50 cm is placed in a uniform field E = 7.50 × 10^3 N/C with edges parallel to the field lines (field enters the
Svetllana [295]

Answer:

a) \Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}, b) \Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}, c) \Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

Explanation:

a) The net flux through the cube is:

\Phi_{net}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}+(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}

b) The flux through the right face is:

\Phi_{right}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}

c) The flux through the left face is:

\Phi_{left}=(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}

\Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}

5 0
3 years ago
Read 2 more answers
The measure of how much salt will dissolve into 100g of water is _______________ .
Bingel [31]
The measure of how much salt will dissolve into 100g of water is _solution_ .
8 0
3 years ago
Read 2 more answers
A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to
jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire  =3.7\ MA

b) Current at the center of the circular coil =2.48\times 10^{5}\ A

c) Current near the center of a solenoid 236.8\ A

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}

\mu=4\pi \times 10^{-7}\ \frac{henry}{m}

Plugging the values,

Conversion 1\times 10^6 A = 1\ MA,and 2cm=\frac{2}{100}=0.02\ m

I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA

⇒Magnetic Field at the center due to circular coil (at center) is given by,B=\frac{\mu\times I (N)}{2(a)}

So I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A

⇒Magnetic field due to the long solenoid,B=\mu\ nI=\mu (\frac{N}{l})I

Then I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A  

So the value of current are  3.7 MA,2.48\times 10^{5} A and 236.8\ A respectively.

8 0
2 years ago
Why isn't Coulomb's law valid for dielectric objects, even if they are spherically symmetrical?
marshall27 [118]

Answer:

Explanation:

The "traditional" form of Coulomb's law, explicitly the force between two point charges. To establish a similar relationship, you can use the integral form for a continuous charge distribution and calculate the field strength at a given point.

In the case of moving charges, we are in presence of a current, which generates magnetic effects that in turn exert force on moving charges, therefore, no longer can consider only the electrostatic force.

4 0
3 years ago
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