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2 years ago

4. The state of Neveda has 70 million arces of land. If 90%

2 answers:

6 0

this is the correct answer 

lawyer [7]2 years ago

6 0

7 million acres of land would be not federally owned, because 10% of 70 million is 7 million

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Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio. She sold a th

Licemer1 [7]

Given :

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio.

She sold a third of her holdings in gold in 2009 at a price $953 per ounce. She sold the rest of her gold holdings in 2010 for $1,367 per ounce.

To Find :

What is Prema’s profit in 2009 and 2010.

Solution :

Price of one third ounces of gold, in 2005 is :

P = $414/3 = $138 .

Profit from selling them in 2009 is :

P1 = $(953 - 138) = $815 .

Profit from selling them in 2010 is :

P2 = $( 1367 - ( 414 - 138 ) ) = $1091 .

Therefore, Prema's profit in 2009 is $815 and 2010 is $1091.

Hence, this is the required solution.

5 0

2 years ago

See the question below.

zheka24 [161]

your answer is B i hope this helpss

4 0

2 years ago

Read 2 more answers

The decimal 1,645.43 rounded to the nearest whole number is

Margarita [4]

Answer:

1,645

Step-by-step explanation:

5 0

2 years ago

Find the ratio of the area inside the square but outside the circle to the area of the square in the picture

Eduardwww [97]

Answer:

0.2146

Step-by-step explanation:

From the picture:

The radius of the circle = r. This means that the area of the circle = πr²

Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²

The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²

The ratio of the area inside the square but outside the circle to the area of the square = r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146

5 0

2 years ago

Finding values or k(x) = x - 2 h(x) = x2 +1 (h + k)(2) =

Serjik [45]

Answer:

Step-by-step explanation:

$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

5 0

2 years ago