Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
The mass of the water accumulated in the bucket after 3.20s is:
To determine the weight of the water accumulated in the bucket, we have:
For the speed of the water before hitting the bucket; we have:
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
F = 1.68 N
Finally, the reading scale is:
= 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
-11776.36 N
This force is attractive since both charges are of opposite sign
Explanation:
Given that
Distance between the spheres = 2.73 cm =0.0273 m
where K is Coulomb's constant =
According to coulombs law we know that force between two charges is given by
This force is attractive since both charges are of opposite sign
Answer:
Explanation:
We shall find first the distance where electric field is E/4 .
Let the charge be Q and distance be d where electric field is E . From the coulomb's Law
E = k Q / d²
Let distance be d₁ where field is E/4
E/4 = kQ / d₁²
Dividing the two equation
4 = d₁² / d²
d₁ = 2d
We shall have to find Potential at d₁ which is equal to 2 d .
Potential at d₁
V = k Q / 2d
= kQ d / 2d²
= E d / 2 . where d is distance of the point where field is E .
it is a transverse wave
A transverse wave is the one that sets the particles of medium into oscillations perpendicular to the direction of wave propagation. So yes, a transverse wave needs a materialistic medium to propagatee.
Examples of transverse waves include:
ripples on the surface of water.
vibrations in a guitar string.
a Mexican wave in a sports stadium.
electromagnetic waves – eg light waves, microwaves, radio waves.
transverse waves require a material medium and propogate by means of vibrations of the medium perpendicular to the direction of travel. ... Electromagnetic (EM) waves (such as light) are also transverse waves but they do not require a medium and thus can pass through a vacuum
Answer:
4.1 m
Explanation:
Given :
Mass of the block = m = 2 kg.
Initial velocity = = 8 m/s
Angle of the incline = α = 30°
Coefficient of friction = μ = 0.35
Distance moved up the incline is calculated using the work energy theorem.
Work done by the net force = change in kinetic energy of the object.
Net work = work done by friction + work done by the gravity component.
(- mg sin 30 - μ mg cos 30 ) d =
m cancels out when divided on both sides with m.
- [(9.8 sin 30 - ( 0.35 × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )
⇒ -7.87 d = -32
⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m