Answer:
x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically
x+y+2=-5 equation 1
-2x-y+2=-1 equation 2
x-2y-2=0 equation 3
Add equation 1 + 2+ 3
x+y+2=-5 + -2x-y+2+1 + x-2y-2
x+y+2= -7+2+1-2x+x+y
x+y+2= -4-x+y
x+y+2+4+x-y= 0
2x+6= 0
2x= -6
divide both side by 2
x= -3
from equation 1 insert x
x+y+2=-5
since x=-3
then, -3+2+y= -5
-1+y= -5
y= -5+1
y= -4
Step-by-step explanation:
Answer: B. 2.5 in
Step-by-step explanation:
From the given right angle triangle,
the hypotenuse of the right angle triangle is the unknown side.
With m∠32 as the reference angle,
the adjacent side of the right angle triangle is 4 in
the opposite side of the right angle triangle is w
To determine w, we would apply
the tangent trigonometric ratio which is expressed as
Tan θ = opposite side/adjacent side. Therefore,
Tan 32 = w/4
w = 4tan32 = 4 × 0.625
w = 2.5 in
The answer to this question is C
Answer:
11 and 12
Step-by-step explanation:
x(x+1)=132
x^2+x=132
x^2+x-132=0
(x-11)(x+12)=0
x = 11 or x = -12
when x=11 ,
x+1=12
11*12=132
