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g100num [7]
3 years ago
15

What is a, the initial amount, for the function: f(x) = 300(1.16)*?

Mathematics
1 answer:
jeka943 years ago
6 0
<h3>Answer:   300</h3>

====================================================

Explanation:

One general template of exponential functions is

f(x) = a*(b)^x

The 'a' is the initial amount, which in this case is a = 300

----------------------

Extra info:

The b is the base of the exponential, which is b = 1.16

The value of b is helpful to determine if you have exponential growth or decay, and how much of either. Because b = 1.16 is greater than 1, it indicates exponential growth. The rate of growth is found by solving 1+r = 1.16 to get r = 0.16, which leads to 16% growth.

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The y-intercept is -3 because that is where the line hits the y-axis.

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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
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Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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