Answer:
i think that is 4
Step-by-step explanation:
fydxudugxxfjg
Answer:
B
Step-by-step explanation:
Here is the complete question :
Benjamin is selecting embellishments for a child’s dresser. There are 9 wooden embellishments, 5 ceramic embellishments, and 8 metal embellishments to choose from, shown in the table below. He picks a wooden embellishment, a ceramic embellishment, and a metal embellishment. What is the probability that he picks one of the clouds, one of the dogs, and one of the stars?
Wooden Embellishments Ceramic Embellishments Metal Embellishments
2 hearts 2 cats 3 stars
3 clouds 3 dogs 5 squares
4 birds
A.1/27
B. 3/40
C. 1/9
D.3/8
Answer:
x = 8
Step-by-step explanation:
Since < A and < B are vertical angles, then it means that they have the same measure.
Given that m < A = (3x - 21)°, and m < B = (2x - 13)°:
We can set up the following equation to solve for the value of x:
m < A = m < B
(3x - 21)° = (2x - 13)°
3x - 21 = 2x - 13
Subtract 2x from both sides:
3x - 2x - 21 = 2x - 2x - 13
x - 21 = -13
Add 21 to both sides to isolate and solve for the value of x:
x - 21 + 21 = -13 + 21
x = 8
We must verify if we have the correct value for x by plugging in 8 into the equality statement:
(3x - 21)° = (2x - 13)°
[3(8) - 21]° = [2(8) - 13]°
(24 - 21)° = (16 - 13)°
3° = 3° (True statement. This means that we have the correct value for x).
Therefore, the value of x = 8.
Please mark my answers as the Brainliest, if you find this solution helpful :)
![\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20x%3D3%5Cimplies%20%26x-3%3D0%5C%5C%20x%3D1%2B3i%5Cimplies%20%26x-1-3i%3D0%5C%5C%20x%3D1-3i%5Cimplies%20%26x-1%2B3i%3D0%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28x-3%29%28x-1-3i%29%28x-1%2B3i%29%3D0%20%5C%5C%5C%5C%5C%5C%20%28x-3%29%5Cunderset%7B%5Ctextit%7Bdifference%20of%20squares%7D%7D%7B%28%5Bx-1%5D-3i%29%28%5Bx-1%5D%2B3i%29%7D%3D0%5Cimplies%20%28x-3%29%28%5Bx-1%5D%5E2-%5B3i%5D%5E2%29%3D0%20%5C%5C%5C%5C%5C%5C%20%28x-3%29%28%5Bx%5E2-2x%2B1%5D-%5B3%5E2i%5E2%5D%29%3D0%5Cimplies%20%28x-3%29%28%5Bx%5E2-2x%2B1%5D-%5B9%28-1%29%5D%29%3D0)
[ correction added, Thanks to @stef68 ]
![\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)](https://tex.z-dn.net/?f=%5Cbf%20%28x-3%29%28%5Bx%5E2-2x%2B1%5D%2B9%29%3D0%5Cimplies%20%28x-3%29%28x%5E2-2x%2B10%29%3D0%20%5C%5C%5C%5C%5C%5C%20x%5E3-2x%5E2%2B10x-3x%5E2%2B6x-30%3D0%5Cimplies%20x%5E3-5x%5E2%2B16x-30%3Df%28x%29%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bapplying%20a%20translation%20with%20a%20-2f%28x%29%7D%7D%7B-2%28x%5E3-5x%5E2%2B16x-30%29%3Df%28x%29%7D%5Cimplies%20-2x%5E3%2B10x%5E2-32x%2B60%3Df%28x%29)
Answer:
CAN U MAKE THE PICTURE BIGGER
Step-by-step explanation:
