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3 years ago

7

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

1 answer:

Ghella [55]3 years ago

4 0

Use ideal gas equation:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
convert kPa to atm. 1 Pa = 9.8 x 10^{-6} atm
T = 293 K
V = 6.8 L
R = 1/12
put all values.
So, n = 0.272

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2 years ago

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Then 75 moles of SiC will be produce from:

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3 years ago

A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d

g100num [7]

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$moles = \frac{Mass\ taken}{Molar\ mass}$

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<u>The volume of 0.24925M stock solution added = 0.40 L </u>

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3 years ago