C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
is a combustion reaction
Explanation:
In a combustion reaction a chemical substance (usually organic substances) are reacted with oxygen to form the most stable oxides and heat.
CH₄ + 2 O₂ → CO₂ + 2 H₂O
In a double displacement reaction two compounds exchange elements.
AB + CD → AC + BD
In a decomposition reaction a compound is split into simpler substances.
AB → A + B
In a synthesis reaction two elements are combined to form another compound. A + B → AB
In a single displacement reaction a compound exchange one of its elements.
AB + C → AC + B
Learn more about:
types of chemical reactions
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Answer:
We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.
Explanation:
- Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution.
<em>(MV) before dilution = (MV) after dilution.</em>
M before dilution = 1.0 M, V before dilution = ??? mL.
M after dilution = 0.2 M, V after dilution = 100 mL.
<em>∴ V before dilution = (MV) after dilution / M before dilution </em>= (0.2 M)(100 mL) / (1.0 M) = <em>20.0 mL.</em>
<em>So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.</em>
i don't know but try putting this diagram into a question on google. you should be able to get some type of answer if not the right answer. good luck and * hint* you can make a really good question out of the sentence on top of the DIAGRAM. I hope this was helpful. please let me know in the comments: )
Answer:
Explanation:
Glucose reacts with oxygen do produce carbon dioxide and water:
Given a daily mass of glucose:
Find moles of glucose:
From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:
Convert this into mass using the molar mass of carbon dioxide:
This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:
