Answer:
<h2>11</h2>
Step-by-step explanation:
Given h(t) = t²+t+ 12 and k(t) = √t-1, we are to find k(k.h)(10)
k{h(t)} = k{ t²+t+ 12}
Since k(t)= √t-1, we will replace the variable t in the function with t²+t+ 12
k(h(t)) = √{(t²+t+ 12)-1}
k(h(t)) = √t²+t+12-1
k(h(t)) = √t²+t+11
Substituting t = 10 into the resulting function;
k(h(10)) = √(10)²+(10)+11
k(h(10)) = √100+10+11
k(h(10)) = √121
<em>k(h(10))= 11</em>
<em></em>
<em>hence the value of (k compose h) (10) is 11</em>
Answer:
huh what does this mean
Step-by-step explanation:
122+6
Step-by-step explanation:
it is the third one because 4×32 is 122, but 4×6 is 24 not 6
Solve 5+57+4+6+9+2+58+532+790
The correct answer is 1463