The answer 160 for 2/3 of a cup
The answer is C. 7.1 feet.
I hope this helps.
Answer:
2 x 3 x 19
Step-by-step explanation:
because 2 x 3 is 6 and 6 x 19 is 114
Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.
Given:
Ray QS bisects ∠PQR.
m∠PQS = 3x
m∠SQR = 5x-20
To find:
The value of x and m∠PQR
Solution:
Ray QS bisects ∠PQR. So,
![m\angle PQS=m\angle SQR](https://tex.z-dn.net/?f=m%5Cangle%20PQS%3Dm%5Cangle%20SQR)
![3x=5x-20](https://tex.z-dn.net/?f=3x%3D5x-20)
![3x-5x=-20](https://tex.z-dn.net/?f=3x-5x%3D-20)
![-2x=-20](https://tex.z-dn.net/?f=-2x%3D-20)
![x=10](https://tex.z-dn.net/?f=x%3D10)
The value of x is 10.
Now,
![m\angle PQR=m\angle PQS+m\angle SQR](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3Dm%5Cangle%20PQS%2Bm%5Cangle%20SQR)
![m\angle PQR=3x+5x-20](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3D3x%2B5x-20)
![m\angle PQR=8x-20](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3D8x-20)
Put x=10,
![m\angle PQR=8(10)-20](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3D8%2810%29-20)
![m\angle PQR=80-20](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3D80-20)
![m\angle PQR=60](https://tex.z-dn.net/?f=m%5Cangle%20PQR%3D60)
Therefore, the m∠PQR is 60 degrees.