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3 years ago

9

A company sold for $3,000 a plant asset that had a cost of $10,000 and accumulated depreciation of $7,500. what gain or loss did

the company experience?

1 answer:

alexdok [17]3 years ago

6 0

The company lost 4,300 dollars because the sold if for 7,300

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The price of an Item has been reduced by 80%. The original price was $65. What is the price of the item now?

PIT_PIT [208]

Answer:

$13

Step-by-step explanation:

multiply 65 by 80 then divide by 100, you get 52, so subtract 65 from 52 you get 13

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3 years ago

A triangle has sides with lengths of 3 yards, 4 yards, and 5 yards. Is it a right triangle?

yulyashka [42]

Answer:

It is a right triangle

Step-by-step explanation:

Depending on how you make the triangle if 3 is A 4 is B and 5 is C then the Pythagorean Theorm would be correct and it would be a right triangle.

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3 years ago

Read 2 more answers

Suppose that the function f is defined. , for all real numbers, as follows.

aivan3 [116]

Answer: <em>The values of......</em>

<em> $f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0$ </em>

Step-by-step explanation:

Given function is: $\left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.$

For $f(-5),$ the value of $x$ is -5, which is not equal to -2.

So, $f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}$

For $f(-2),$ the value of $x$ is -2.

So, $f(-2)= -1$

For $f(4),$ the value of $x$ is 4, which is not equal to -2.

So, $f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0$

5 0

3 years ago

Priya starts with $50 in her bank account. She then deposits $20 each week for 12 weeks.

liubo4ka [24]

Answer:

10 weeks

Step-by-step explanation:

20x+50=250

First subtract 50 from both sides, which gives you 20x=200

then divide 20 from both sides which gives you x=10

3 0

3 years ago

H(t)= (t+3)^2 + 5

oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

$\frac{h(-1)-h(-5)}{-1+5}$

so we find:

$h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9$

then the average rate of change becomes:

$\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0$

5 0

3 years ago