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3 years ago

9

A company sold for $3,000 a plant asset that had a cost of $10,000 and accumulated depreciation of $7,500. what gain or loss did

the company experience?

1 answer:

alexdok [17]3 years ago

6 0

The company lost 4,300 dollars because the sold if for 7,300

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Divide 33 into 2 groups so the ratio can be 4 to 7

svet-max [94.6K]

To do this task the best way is always add both "sides" of ratio and divide whole group by this sum.sum=4+7=1133:11=3Now we know how much is 1 and we can multiply by 4 and by 7 to find the answer.3*4=12 - first group3*7=21 - second group
Your result is ok.

7 0

3 years ago

Read 2 more answers

Please help. Write as a single logarithm, a) log(13)+log(4) b) log(small 5)(14)-log(small 5)(2)

dsp73

Answer:

a) $\log 52$

b) $\log_57$

Step-by-step explanation:

Use logarithm properties:

$\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}$

Then

a) $\log 13+\log 4=\log 13\cdot 4=\log 52$

b) $\log_514-\log _52=\log _5\dfrac{14}{2}=\log _57$

7 0

4 years ago

What is the solution to the expression -2-3-(-4)?

alexgriva [62]

Answer: -1

-2-3-(-4)
-5-(-4)
-1

5 0

3 years ago

Read 2 more answers

Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo

eduard

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins) $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12

+ 16 dimes $1.60

Total Coins 48 $4.32

8 0

3 years ago

Mr.Ward runs a lot. He ran 45 minutes each day, 5 days each week , for 16 weeks . In that time, he ran 450 miles. What was his a

Savatey [412]

Answer:

7.5 miles per hour.

Step-by-step explanation:

We have been given that Mr. Ward runs a lot. He ran 45 minutes each day, 5 days each week, for 16 weeks.

First of all, we will find time for that Mr. Ward ran in 16 weeks.

We will multiply 5 by 16 to find number of days for that Mr. Ward ran and then we will multiply the result by 45 minutes to find the time.

$\text{Time for that Mr. Ward ran in 16 weeks}=16\times 5\times 45\text{ minutes}$

$\text{Time for that Mr. Ward ran in 16 weeks}=3600\text{ minutes}$

Now, we will divide 3600 minutes by 60 minutes to convert time into hours as:

$\text{Hours}=\frac{3600}{60}=60$

Now, we will divide 450 miles by 60 hours to find Mr. Ward's average speed as:

$\text{Mr. Ward's average speed}=\frac{450\text{ miles}}{\text{60 hours}}$

$\text{Mr. Ward's average speed}=\frac{7.5\text{ miles}}{\text{ Hour}}$

Therefore, Mr. Ward's average speed in 7.5 miles per hour.

7 0

3 years ago